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leonid [27]
4 years ago
14

compare and contrast the results of a crash while the passengers are not wearing seat belts and while they are wearing seat belt

s
Physics
1 answer:
timofeeve [1]4 years ago
6 0
One comparison is that both people in the cars (whether they were wearing a seat belt or not) is that they sustain injuries. People are obviously going to get hurt in a crash. A prime difference though is how big of an injury it is. People who were wearing seat belts at the time of a crash are less likely to have serious injuries, while those who weren't wearing seat belts have a higher possibility of sustaining really serious injuries.
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Arrange the homeostasis process in the right sequence.
spayn [35]

1. Cold environment

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3 0
4 years ago
PAY ATTENTION MY QUESTION ASK FOR RADIATION!!!
Anestetic [448]

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Thermal energy moves within the air from the flames to the marshmallow.

Explanation:

Hope it helps

3 0
3 years ago
contractor will use a package emulsion having a specific gravity of 1.25 and relative bulk strength of 130 to open an excavation
tester [92]

Answer:

The burden distance is 7 ft

Solution:

As per the question:

Specific gravity of package emulsion, SG_{E} = 1.25

Specific gravity of diabase rock, SG_{R} = 2.76

Diameter of the packaged sticks, d = 3 in

Now,

To calculate the first trail shot burden distance, B:

B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d

B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22

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5 0
3 years ago
The actual depth of a shallow pool 1.00 m deep is not the same as the apparent depth seen when you look straight down at the poo
DedPeter [7]

Answer:

d' = 75.1 cm

Explanation:

It is given that,

The actual depth of a shallow pool is, d = 1 m

We need to find the apparent depth of the water in the pool. Let it is equal to d'.

We know that the refractive index is also defined as the ratio of real depth to the apparent depth. Let the refractive index of water is 1.33. So,

n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{1\ m}{1.33}\\\\d'=0.751\ m

or

d' = 75.1 cm

So, the apparent depth is 75.1 cm.

4 0
3 years ago
A cylinder of compressed gas has a pressure of 488.2 kPa. The next day the cylinder of gas has a
Luda [366]

Answer:

20 °C

Explanation:

Ideal gas law:

PV = nRT

Rearranging:

P / T = nR / V

Since n, R, and V are constant:

P₁ / T₁ = P₂ / T₂

488.2 kPa / T = 468 kPa / 281.15 K

T = 293.29 K

T = 20.1 °C

Rounded, the temperature was 20 °C.

6 0
4 years ago
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