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sergij07 [2.7K]
3 years ago
14

contractor will use a package emulsion having a specific gravity of 1.25 and relative bulk strength of 130 to open an excavation

in diabase rock, specific gravity 2.76. the drilling equipment available will drill a 4-in. blasthole. the explosive comes packaged in 3-in-diameter sticks. what is the recommended burden distance for the first trail shot? round the calculated burden distance to the nearest foot.
Physics
1 answer:
tester [92]3 years ago
5 0

Answer:

The burden distance is 7 ft

Solution:

As per the question:

Specific gravity of package emulsion, SG_{E} = 1.25

Specific gravity of diabase rock, SG_{R} = 2.76

Diameter of the packaged sticks, d = 3 in

Now,

To calculate the first trail shot burden distance, B:

B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d

B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22

B = 7 ft

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Answer:

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Explanation:

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     u ’= (u-v) / (1- uv / c²)

Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory

The data give is u ’= 0.43c and the initial core velocity v = 0.94c

Let's clear the speed with respect to the observer (u)

      u’ (1- u v / c²) = u -v

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      u (1 + u ’v / c²) = v - u’

      u = (v-u ’) / (1+ u’ v / c²)

Let's calculate

      u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)

      u = 0.51c / (1 + 0.4042)

      u = 0.36c

We repeat the calculation for the other piece

In this case u ’= - 0.35c

We calculate

       u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)

       u = 1.29c / (1- 0.329)

       u = 0.961c

6 0
3 years ago
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andreev551 [17]

Answer:

C)

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Tpy6a [65]
If a negatively charged object is used to charge a neutral object by induction, then the neutral object will acquire a positive charge. And if a positively charged object is used to charge a neutral object by induction, then the neutral object will acquire a negative charge.
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3 years ago
Um avião, após deslocar-se 120 km para nordeste (NE), desloca-se 160 km para sudeste (SE). Sendo um quarto de hora o tempo total
Svetach [21]

Answer:

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d1 = northeast displacement

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Now

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= √40000

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Now the average velocity is

V = ΔS ÷ Δt

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4 0
3 years ago
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Answer:

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3 years ago
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