Question

An aluminum wire of length 1.0 meter has a resistance of 9.0x10^-3 ohm. If the wire were cut into two equal lengths, each length would have a resistance of

Answer 1

Answer:since resistance depends on length, then the resistance will be shared equally since it was cut equally therefore the resistance is

4.5*10^-3 ohm

Explanation:

Answer 2

Answer : The each length would have a resistance of $4.5\times 10^{-3}\Omega$

Explanation :

Let the resistance of equal length of wire be, r

That mean,

$r+r=R$

where,

r = resistance of equal length of wire

R = total resistance of wire = $9.0\times 10^{-3}\Omega$

As we know that resistance is directly proportional to length.

Total resistance of aluminum wire = Sum of resistance of two equal piece of wires

$r+r=9.0\times 10^{-3}\Omega$

$2r=9.0\times 10^{-3}\Omega$

$r=\frac{9.0\times 10^{-3}\Omega}{2}$

$r=4.5\times 10^{-3}\Omega$

Therefore, the each length would have a resistance of $4.5\times 10^{-3}\Omega$