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sashaice [31]
3 years ago
13

The actual depth of a shallow pool 1.00 m deep is not the same as the apparent depth seen when you look straight down at the poo

l from above. How deep (in cm) will it appear to be
Physics
1 answer:
DedPeter [7]3 years ago
4 0

Answer:

d' = 75.1 cm

Explanation:

It is given that,

The actual depth of a shallow pool is, d = 1 m

We need to find the apparent depth of the water in the pool. Let it is equal to d'.

We know that the refractive index is also defined as the ratio of real depth to the apparent depth. Let the refractive index of water is 1.33. So,

n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{1\ m}{1.33}\\\\d'=0.751\ m

or

d' = 75.1 cm

So, the apparent depth is 75.1 cm.

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Ganezh [65]

Answer:

230.4 s

Explanation:

The speed of car A is

v_A = 35 mi/h

and the distance travelled is

d = 10 mi

so the time taken for car A is

t_A = \frac{d}{v_A}=\frac{10 mi}{35 mi/h}=0.286 h

The speed of car B is

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and the distance travelled is

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so the time taken for car B is

t_B = \frac{d}{v_B}=\frac{10 mi}{45 mi/h}=0.222 h

So the difference in time is

\Delta t = t_A - t_B = 0.286 h -0.222 h=0.064 h

Which corresponds to

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so car B arrived 230.4 s before car A.

5 0
3 years ago
A +13.4 nC charge is located at (0,9.4) cm and a -4.23 nC charge is located (4.99, 0) cm. Where would a -14.23 nC charge need to
antiseptic1488 [7]

In order to solve this problem, we will first need to find the electric field at the origin without the 3rd charge

E1 = (9x10^9)(13.4x10^-9)/(9.4x10^-2)^2 = 13648.7 V/m towards the negative y-axis

E2 = (9x10^9)(4.23x10^-9)/(4.99x10^-2)^2 = 15289.1 V/m towards the positive x-axis

The red arrow shows the direction of which the electric field points.

To make the electric field at the origin 0, we must find a location where q3 = the magnitude of q1 and q2

Etotal = sqrt(E1+E2) = 20494.97 V/m

E3 = 20494.97 = (9x10^9)(14.23x10^-9)/(d)^2

d = 0.079 m = 7.9 cm

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Wittaler [7]
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3 years ago
A group of letters used at the start of a word to change its meaning?
Diano4ka-milaya [45]

Answer:

prefix

Explanation:

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When a person collides with an inflated air bag, the impact forces the molecules of gas in the bag closer together. The compression of the gas absorbs the energy of the impact.

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