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sashaice [31]
3 years ago
13

The actual depth of a shallow pool 1.00 m deep is not the same as the apparent depth seen when you look straight down at the poo

l from above. How deep (in cm) will it appear to be
Physics
1 answer:
DedPeter [7]3 years ago
4 0

Answer:

d' = 75.1 cm

Explanation:

It is given that,

The actual depth of a shallow pool is, d = 1 m

We need to find the apparent depth of the water in the pool. Let it is equal to d'.

We know that the refractive index is also defined as the ratio of real depth to the apparent depth. Let the refractive index of water is 1.33. So,

n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{1\ m}{1.33}\\\\d'=0.751\ m

or

d' = 75.1 cm

So, the apparent depth is 75.1 cm.

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A state trooper is traveling down the interstate at 20 m/s. He sees a speeder traveling at 50 m/s approaching from behind. At th
Vaselesa [24]

Answer:

Explanation:

From the given information;

Let assume that the distance travelled by the speeder prior to the time the trooper catches with it to be = d

the time interval to be = t

Then, the speeder speed = distance/time

Making distance the subject; then:

distance (d) = speed × time

d = (50 m/s)t

d = 50 t --- (1)

Now, for the trooper; Using the equation of motion:

d = ut + \dfrac{1}{2}at^2

d = (20)t+\dfrac{1}{2}(2.5)t^2

d = 20t + 1.25t²

Replace the value of d in (1) to the above equation, we have:

50 t = 20 t + 1.25t²

50t - 20t = 1.25t²

30t = 1.25t²

30 = 1.25t

t = \dfrac{30}{1.25}

t = 24 seconds

From (1), the distance far down the highway the trooper will travel prior to the time it catches up with the speeder is:

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8 0
2 years ago
Cell phone conversations are transmitted by high-frequency radio waves. Suppose the signal has wavelength 36.5 cm while travelin
tia_tia [17]

Answer:

f=8.219*10^{8}Hz

Explanation:

We are going to use the formula  v=fλ

Where v= velocity of radio waves

f= frequency

λ= wavelength of wave

  • radio waves are electromagnetic waves and as such they have the speed of light which is 3*10^{8}m/s.
  • also when a wave travels from one medium to another, the wavelength changes while the frequency remains the same.
  • calculating for the frequency of the wave in air also gives us the frequency in the window glass.

f=\frac{v}{λ}

v=3*10^{8}m/s.

λ=36.5 cm = 36.5/100= 0.365m

f=\frac{3*10^{8}m/s.}{0.365m}

f=8.219*10^{8}Hz

7 0
3 years ago
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