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3 years ago

10

There is a 5% per year decline in water in the following reservoir. if the reservoir had 2000 gallons of water in year 2001, how

much water will remain in 2017? set up the exponential decay function and solve showing your work
please help me

1 answer:

egoroff_w [7]3 years ago

5 0

Answer is 85% count by 5 17 times 5=5%

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F(x)=3x+5 and g(x)=2x+1<br><br>value of x

AlekseyPX

You can treat x and 2x+1 just as though they are real numbers.

So f(2x+1) = 3(2x+1) - 5 = 6x + 3 - 5 = 6x - 2

In the above, I made use of something called the distributive law which says that if a,b and c are real numbers, then a(b+c) = ab + ac.

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The sales tax rate in a certain state is 8%. How much would you pay in total for a taxable item that costs $25.25?

faust18 [17]

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3 years ago

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Mario is constructing a wall around a rectangular area which will cover a maximum of 60 square feet. The length of the wall will

Feliz [49]

Answer:

$W \le 6$

Step-by-step explanation:

Given

$Area = 60ft^2\ (max)$

$Length = 10ft$

Required

Represent the width as an inequality

First, we represent the area as an inequality.

$Area = 60ft^2\ (max)$

max as used above means less than or equal to.

So, we have:

$Area \le 60$

The area of a rectangle is:

$Area = L * W$

So, we have:

$L * W \le 60$

Substitute 10 for L

$10 * W \le 60$

Divide both sides by 10

$\frac{10 * W}{10} \le \frac{60}{10}$

$W \le \frac{60}{10}$

$W \le 6$

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3 years ago

Help asap im in a quiz!

goldfiish [28.3K]

The answer should be b

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3 years ago

In a class of 40 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

ladessa [460]

Answer:3

Step-by-step explanation:

Given

There are total 40 students in a class

No of students with Pierced Nose n(N)=7

No of students with Pierced ear n(E)=36

and we know using sets

$n\left ( N\cup E\right )=n\left ( E\right )+n\left ( N\right )-n\left ( N\cap E\right )$

where $n\left ( N\cup E\right )=$ Students either nose or ear Pierced

$n\left ( N\cap E\right )=$ no of students having both nose and ear pierced

$40=7+36-n\left ( N\cap E\right )$

$n\left ( N\cap E\right )=43-40=3$

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3 years ago