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Evgen [1.6K]
3 years ago
14

Find a formula for the general term of the sequence, assuming that the pattern of the first few terms continues. 2, 9, 16, 23

Mathematics
2 answers:
gayaneshka [121]3 years ago
5 0
This is an arithmetic sequence which means all of these terms are all the same distance from one another. 
an=a1+d(n-1)
an=2+7(n-1)
an=2+7n-7
Answer: an=7n-5
musickatia [10]3 years ago
3 0
It increases by 7 and it's arithmetic progression:
Where d = 7
a = 2

and the formula will be

a_{n} = a + d (n-1) = 2 + 7*(n-1)

Where n starts from 1 and continues to the infinity
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Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
Mazyrski [523]

We can use the fact that, for |x|,

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

Notice that

\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1{1-x}\right]=\dfrac1{(1-x)^2}

so that

f(x)=\displaystyle\frac5{(1-x)^2}=5\frac{\mathrm d}{\mathrm dx}\left[\sum_{n=0}^\infty x^n\right]

f(x)=\displaystyle5\sum_{n=0}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=1}^\infty nx^{n-1}

f(x)=\displaystyle5\sum_{n=0}^\infty(n+1)x^n

By the ratio test, this series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(n+2)x^{n+1}}{(n+1)x^n}\right|=|x|\lim_{n\to\infty}\frac{n+2}{n+1}=|x|

so the series has radius of convergence R=1.

5 0
2 years ago
a box contains ten cards labeled q, r, s, t, u, v, w, x, y, and z. one card will be randomly chosen. what is the probability of
JulijaS [17]

Answer: t, and u

Step-by-step explanation:

6 0
3 years ago
Match each expression on the left with an equivalent expression on the right
Lana71 [14]
Answer: See explanation
Step-by-step explanation:
You didn't give the expressions but here are some expressions
a. ✓4x²y^4. 1. 2x✓y
b. ✓8x²y. 2. 2y✓2x
c. ✓4x²y. 3. 2xy²
d. ✓16xy². 4. 2x✓2y
e. ✓8xy². 5. 4y✓x
a. ✓4x²y^4 = ✓4 × ✓x² × ✓y^4
= 2 × x × y²
= 2xy²
Therefore, ✓4x²y^4 = 2xy²
b. ✓8x²y = ✓8 × ✓x² × ✓y
= ✓4 × ✓2 × ✓x² × ✓y
= 2 × ✓2 × x × ✓y
= 2x✓2y
Therefore, ✓8x²y = 2x✓2y
c. ✓4x²y = ✓4 × ✓x² × ✓y
= 2 × x × ✓y
= 2x✓y
Therefore, ✓4x²y = 2x✓y
d. ✓16xy² = ✓16 × ✓x × ✓y²
= 4 × ✓x × y
= 4y✓x
Therefore, ✓16xy² = 4y✓x
e. ✓8xy² = ✓8 × ✓x × ✓y²
= ✓4 × ✓2 × ✓x × ✓y²
8 0
2 years ago
Read 2 more answers
Joe plotted the points (2, 0.5), (1, 1), and (0.5, 2), and claimed that these points represent an inverse variation relationship
Kobotan [32]
Xy = 1 for all points.

 We are going to demonstrate this affirmation:
 (2) * (0.5) = 1
 (1) * (1) = 1
 (0.5) * (2) = 1
 Therefore, the relationship between the ordered pairs is inverse.
 The relationship between the ordered pairs is:
 y = 1 / x

 Answer: 
 xy = 1 for all points.
7 0
3 years ago
If f(x)=x-6/x, g(x)=x+4 and h(x)= 3x-2 (h*f*g)(x)
Lelechka [254]

Answer:

-14 + x\4 + x

Step-by-step explanation:

Start by plugging the g(x) function into the f(x) for every "x" you see, then take THAT answer and plug into the h(x) function for that "x" you see. You will arrive at the above answer.

5 0
3 years ago
Read 2 more answers
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