Question

Georgia is jogging with a velocity of 4 m/s when she accelerates at 2 m/s2 for 3 seconds. How fast is Georgia running now?

Answer 1

Georgia is moving by uniformly accelerated motion, with initial velocity 
$v_0 =4 m/s$
and with constant acceleration  of
$a=2 m/s^2$
so her velocity at time t is given by
$v(t) = v_0 + at = 4 m/s + (2 m/s^2)(3 s)= 10 m/s$
So now Georgia is running at 10 m/s.