Answer:
I know one way of refraction in this photo is how you can see a mirror like image of the man while he is under water on the waves on the surface
Explanation:
I hope that this helps
Answer:
35.67°
Explanation:
Given that:
angle of glance(i) = 30°
Depth of water d = 1.20 m
The height of the observer above the water is h = 3.10 m - 1.20 m
= 1.90 m
Refractive Index of water (n) = 1.33
Using Snell's Law at the water air interface;
n₁ × sin (90- i) = n₂ × sin (90 - r)
1 × cos (i) = 1.33 cos (r)
r = cos ⁻¹ (cos 30/1.33)
r = 49.4
D = h/tan (i)
D = 1.9 / tan (30)
D = 3.291 m
D' = d/tan (r)
D' = 1.2 m/ tan (49.4)
D' = 1.0285 m
∴ the angle at which the spear is to be thrown is :
x = tan⁻¹ [(h+d)/(D+D')]
x = tan⁻¹ [(1.9+ 1.2)/(3.291+1.0285)]
x = tan⁻¹ [3.1/4.3195]
x = 35.67°
∴ At an angle of 35.67° below horizontal is required for you to throw the spear in order to hit the target.
Answer:
The heat is 10458 J and 15480 J.
Explanation:
Given that,
Temperature T₁ = 404 K
Temperature T₂ = 298 K
Work done = 2740 J
If the temperature T₁ =298 k
Temperature T₂ = 245 K
We need to calculate the heat
Using efficiency formula
...(I)
We need to calculate the efficiency
Using formula of efficiency
Put the value of efficiency in equation (I)
Again, we need to calculate the efficiency
We need to calculate the heat
Using equation (I)
Hence, The heat is 10458 J and 15480 J.