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aleksley [76]
4 years ago
5

James drove his car down a mountain road at an average rate of 30 mph and retunred over the same road at an average rate of 20 m

ph. How far did he drive down the road before he turned around and drove back if his trip took 5 hours?
A. 1B. 2C. 3D. 4E. 5
Physics
1 answer:
ollegr [7]4 years ago
7 0

Answer:

150 miles

Explanation:

5 times 30 is 150

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Acceleration question plz help
andrezito [222]
For #5 It's helpful to draw a free body diagram so you know which way the forces are acting on the block.

the weight mg is acting downwards, and you need to find the vertical and horizontal components of mg using sin and cosine. so do 15x9.8xsin40 which is the force. Assuming no friction, this is the only force acting on the block, as the forces on the vertical plane cancel out i.e the normal force and weight of the block.

after, just do F=ma And since you know F and m, solve for a.
3 0
3 years ago
Two cars are traveling around identical circular racetracks. Car A travels at a constant speed of 20 m/s. Car B starts at rest a
Tomtit [17]

Answer:

b. it has the same centripetal acceleration as car A.

Explanation:

According to the question, the data provided is as follows

Constant speed of car A = 20 m/s

Constant tangential acceleration until its speed is 40 m/s

Based on the above information, the true statement is the same centripetal acceleration as car A because

As we know that

Centripetal acceleration is

= \frac{V^2}{r}

where,

V^2 = velocity

r = radius of the path

Now if both car A and car B moving in the same or identical circular path having the same velocity so in this case there is the same centripetal acceleration for that particular time

hence, the second option is correct

3 0
4 years ago
Two horizontal pipes have the same diameter, but pipe B is twice as long as pipe A. Water undergoes viscous flow in both pipes,
zheka24 [161]

Answer:

c) 2Q

Explanation:

From the given information:

The pressure inside a pipe can be expressed by using the formula:

\Delta P = \dfrac{128 \mu L Q}{\pi D^4}

Since the diameter in both pipes is the same, we can say:

D = D_A = D_B

where;

length of the first pipe A L_A = L and the length of the second pipe B L_B = 2L

Since the difference in pressure is equivalent in both pipes:

Then:

\dfrac{128 \mu L_1Q_1}{\pi D_1^4} = \dfrac{128 \mu L_2Q_2}{\pi D_2^4}

\dfrac{ L_1Q_1}{D_1^4} = \dfrac{ L_2Q_2}{D_2^4}

\dfrac{ LQ_1}{D^4} = \dfrac{ 2LQ}{D^4}

\mathbf{Q_1 = 2Q}

6 0
3 years ago
Define the term mid-ocean ridge in simple, easy-to-understand words. Thanks :)
Likurg_2 [28]
According to wikipedia <em>a mid-ocean ridge is an underwater mountains system formed by tectonic plates.

</em>Happy studying!<em>
</em>
6 0
4 years ago
CAN ANYONE PLEASE HELP ME WITH THIS ONE ITS URGENTLY NEEDED
denis-greek [22]

Answer:

Explanation:

conservation of momentum

initial momentum is zero

Lets say that m₁ moves along the x axis

and m₂ moves along the y axis

in the y direction

0 = m₁(0) + m₂(30) + m₃(vy)

0 = m₁(0) + m₂(30) + 3m₂(vy)

-3m₂(vy) = m₂(30)

vy = -10 m/s

in the x direction

0 = m₁(30) + m₂(0) + m₃(vx)

0 = 2m₂(30) + m₂(0) + 3m₂(vx)

-3m₂(vx) = 2m₂(30)

vx = -20 m/s

v = √(-10² + -20²) = 10√5 m/s ≈ 22.36 m/s

θ = arctan(-10/-20) = 206.56505... ≈ 206.6°  CCW from the + x axis

4 0
3 years ago
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