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nadezda [96]
3 years ago
14

When subtracted, what is the simplified form of (5 − 3i) − (4 + 6i)? Write the answer in standard form, a + bi, where a and b ar

e real numbers.
Mathematics
1 answer:
guapka [62]3 years ago
5 0
(5 - 3i) - (4 + 6i)      Remove the brackets. Be careful with those on the right.
5 - 3i - 4 - 6i            Did you notice how the second set worked. That - sign affected both terms inside the brackets. Now collect your like terms.

5 - 4 - 3i - 6i   The - 3i and - 6i  act like money. You are three dollars in the hold and you spend another 6. Where does that put you ?
1 - 9i              You are now 9 dollars in the whole.


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3 0
3 years ago
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Determine the number of ways she can arrange her daily schedule.
natita [175]

Answer:

This can be found by using the permutations and combinations formuals.

Combinations being the C equation and Permutations being the P equation.

P(n,r)=\frac{6!}{(6-6)!}=720

Explanation:

A permutation is used for the list of data (where the order of the data matters) and the combination is used for a group of data (where the order of data doesn't matter).

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2 years ago
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Azmyne decided to spend 6 1/2 hours studying over the weekend. She spent 1 1/4 hours studying on Friday evening and 2 2/3 hours
nata0808 [166]

Answer: 2\ \dfrac{7}{12}\ \text{hours}

Step-by-step explanation:

Given

Azmyne decided to study a total of 6\ \frac{1}{2}\ hours

She spent 1\ \frac{1}{4}\ hours on Friday and  2\ \frac{2}{3}\ hours on Saturday

Hours spent on Friday

\Rightarrow 1\ \frac{1}{4}=\frac{5}{4}\ hours

Hours spent on Saturday

\Rightarrow 2\ \frac{2}{3}=\frac{8}{3}\ hours

She must study for

\Rightarrow \dfrac{13}{2}-\dfrac{5}{4}-\dfrac{8}{3}\\\\\Rightarrow \dfrac{13\times6-5\times3-8\times4}{12}=\dfrac{78-15-32}{12}\\\\\Rightarrow \dfrac{31}{12}=2\ \frac{7}{12}\ \text{hours}

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3 years ago
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Answer:

  y²/324 -x²/36 = 1

Step-by-step explanation:

Where (0, ±b) are the ends of the transverse axis and y = ±(b/a)x describes the asymptotes, the equation of the hyperbola can be written as ...

  y²/b² -x²/a² = 1

<h3>Application</h3>

Here, we have transverse axis endpoints of (0, ±18) and asymptotes of y = ±3x, so we can conclude ...

  b = 18

  b/a = 3   ⇒   a = 18/3 = 6

The equation of the hyperbola in standard form is ...

  y²/324 -x²/36 = 1

7 0
2 years ago
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