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kipiarov [429]
3 years ago
11

How to label tables with unit Rates

Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0
To label a table with unit rates, say you have 1024/17 divide 1024 by 17, because that is what you divide 17 by to get 1. So the answer would be 60 4/17 / 1
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If someone could figure out the top question that would be great, thank you so much!
Maurinko [17]
I think i only get some of it. this is what i did

x = -3 to 4y = 0.3 to 3if we use -3 and 3a < -1 < b
a= -2 to infiniteb= 0 to infinite
5 0
3 years ago
X − (y − y)= for x = 3 and y = 6
dusya [7]

Answer:

3

Step-by-step explanation:

x − (y − y)

3-(6-6)

3-0

3

3 0
3 years ago
Read 2 more answers
I have a question and I cant seem figure it out. It says( Triangle ABC is a right triangle. Angle B is the right angle, side A i
pychu [463]

Answer:

you need to draw a triangle of given dimensions

Step-by-step explanation:

if B is right angle triangle then you can assume that either AB or BC is base and other one is perpendicular. So that makes AC hypotenuse

so let's assume BC is base of 6 cm. so draw a base of 6 cm line , name it BC

then draw a 90 degree angle on B keeping BC as Base . now length of perpendicular would be 4.5 cm. this perpendicular would be AB

no join A and C . length of AC should be 7.5 cm. if it's not then something is wrong in given question.

8 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
3 years ago
The source of the error when a computer system fails are either the disk drive, the computer memory, or the operating system. Ve
faltersainse [42]

Answer:

The probability of an operating system error given that a failure has ocurred is P(O/E)= 0.19

Step-by-step explanation:

Hello!

There are three different sources of error when a computer system fails:

D: disk drive error. ⇒ P(D)= 0.50

M: computer memory error. ⇒P(M)= 0.20

O: operating systems error. ⇒ P(O)= 0.30

According to the component perdormance standard:

The probability of failure "E", given that there is a disk drive error is P(E/D)= 0.40

The probability of failure "E", given that there is a computer memory error is P(E/M)= 0.6

The probability of failure "E", given that there is a operating system error is P(E/O)= 0.25

You need to calculate the probability of an operating system error given that a failure has ocurred, symbolically:

P(O/E)

P(O/E)= \frac{P(OnE)}{P(E)}

To reach the probability of the marginal E you have to add all intersections between the event "E" and the events "D", "M" and "O"

       D           M             O       Total

E:  P(E∩D); P(E∩M); P(E∩O);  P(E)

Using the formula of the conditional probability I'll clear all three intersections using the known probabilities:

General formula: P(A/B)= \frac{P(AnB)}{P(B)} ⇒ P(AnB)= P(A/B)*P(B)

P(E∩D)= P(E/D)*P(D)= 0.4*0.5= 0.2

P(E∩M)= P(E/M)*P(M)= 0.6*0.2= 0.12

P(E∩O)= P(E/O)*P(O)= 0.25*0.3= 0.075

P(E)= P(E∩D) + P(E∩M) + P(E∩O)= 0.2+0.12+0.075= 0.395

P(O/E)= \frac{P(OnE)}{P(E)} = \frac{0.075}{0.395}= 0.189 = 0.19

I hope it helps!

7 0
3 years ago
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