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snow_tiger [21]
3 years ago
13

Consider the distance formula d=16t^2 where d is the distance in feet that an object travels and t is the time in seconds that i

t travels. How long does it take an object to travel 624 feet?
best answer gets brainliest,
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
7 0

Answer:

The Formula D 16t 2

The formula s=16t^2 is used to approximate the distance s, in feet, that an object falls freely from the rest in t seconds. The height of a building is. The formula s=16t^2 is used to approximate the distance s, in feet, that an object falls freely from the rest in t seconds.

Step-by-step explanation:

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Help solve the above equation ​
Tresset [83]

Answer:

\dfrac{1}{27}

Step-by-step explanation:

n^{-\frac{2}{3}}=9

Rewrite:

\dfrac{1}{\sqrt[3]{n^2}}=9\\\\9\sqrt[3]{n^2}=1

Cube both sides:

729n^2=1

Divide both sides by 729:

n^2=\dfrac{1}{729}

Take the square root of both sides:

n=\sqrt{\dfrac{1}{729}}=\dfrac{1}{27}

Hope this helps!

5 0
3 years ago
A paint company charges $5.00 per square foot and a $380.00 flat fee. The company is offering a 10% discount on the total painti
rjkz [21]

Answer:

y=(5x+380)/10

Step-by-step explanation:

3 0
3 years ago
Is y= 1/4x-2 parallel <br>or not?​
lisabon 2012 [21]

Answer:

yes

Step-by-step explanation:

yes cause it equals 8 and 8 is even

4 0
3 years ago
Aggie is an Australian exchange student in China, and she currently has 14,000 yuan in her bank account. If the exchange rate ch
Evgen [1.6K]
Find the value in Australian dollars for each exchange rate. 
<span>1st exchange rate: </span>
<span>14000/6.21= $2254.43 </span>

<span>2nd exchange rate: </span>
<span>14000/6.37= $2197.80 </span>

<span>Find the difference between the two: </span>
<span>$2254.43 - $2197.80 = $56.63 </span>

Since the first value is greater than your second one Aggie lost money and your answer is <span>It decreases by $56.63.</span>
3 0
3 years ago
Salaries of 45 college graduates who took a statistics course in college have a​ mean, x overbar​, of $ 61 comma 300. assuming a
Fiesta28 [93]
We are given:
sample size= n = 45
sample mean = x = 61,300
sample standard deviation =18,246

Since the population standard deviation is not known we will use t distribution to find the confidence interval.

Confidence interval = 99%
Degrees of freedom= n - 1 = 45 – 1 = 44
Critical t value = 2.692

The 99% confidence interval will be:(x-t_{critical}* \frac{s}{ \sqrt{n} },  x+t_{critical}* \frac{s}{ \sqrt{n} }) \\  \\ &#10;(61300-2.692* \frac{18246}{ \sqrt{45} }, 61300+2.692* \frac{18246}{ \sqrt{45} }) \\  \\ &#10;(53978,68622)

Thus, the 99% confidence interval for the population mean is:
53978 to 68622
7 0
4 years ago
Read 2 more answers
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