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pentagon [3]
4 years ago
15

A train travels at a constant speed. What is the train's speed between checkpoints, expressed as a unit rate? Use the informatio

n given in the picture to help you.

Mathematics
2 answers:
madreJ [45]4 years ago
5 0
Remember that the speed is the rate of change of the position with respect to time, so to solve this we are going to use the kinematic equation: S= \frac{d_{f}-d_{i}}{t_{f}-t_{i}}
where 
S is the speed of the train
d_{i} is the initial distance
d_{f} is the final distance 
t_{i} is the initial time 
t_{f} is the final time 

Since checkpoint A is the initial checkpoint, we can infer that d_{i}=105 and t_{i}=2. Similarly, since checkpoint B is the final checkpoint, we can infer that d_{f}=285 and t_{f}=5. Lets replace the values in our kinematic euation:
S= \frac{d_{f}-d_{i}}{t_{f}-t_{i}}
S= \frac{285-105}{5-2}
S= \frac{180}{3}
S=60 mph

We can conclude that the train's speed between checkpoints is 60 mph.
Mrrafil [7]4 years ago
3 0
The checkpoints is 60 mph if you have any questions just ask:)
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enyata [817]

Answer:

144°, 144°, 36°, 36°.

Step-by-step explanation:

Take shorter angle = x

Then the bigger angle = 4x (4 times the other angle)

In a parallelogram, there are 4 angles. Also, in a parallelogram opposite angles are equal to each other.

So,

1 angle = x

2 angle = 4x

3 angle = x

4 angle = 4x

The sum of all 4 angles in a parallelogram = 360°. So,

4x + x + 4x + x = 360°

10x = 360°

x = 360/10

x° = 36°

4x = 36 × 4 = 144°

Angles in the parallelogram = 144°, 144°, 36°, 36°.

Hope it helps ⚜

7 0
2 years ago
Read 2 more answers
In the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3
Lesechka [4]

Answer:

a) The student cannot receive an A in the class.

b) The student must score 119 in the third exams to make an A.  This is clearly not possible, since he cannot make 119 in a 100-points exam.

c) The student can make a B but he must score at least 84 in the third exam.

Step-by-step explanation:

To make an A, the student must score 315 (350 x 90%) in both home and the three exams.

The student who scored 35 (7 + 8 + 7 + 5 + 8) in the homework and 161 (81 + 80), getting a total of 196, is short by 119 (315 - 196) scores in making an A.

To make a B, the student must score 280 (350 x 80%) or higher but not reaching 315.

B ≥ 280 and < 315.

Since, the student had scored 196, he needs to score 84 and above to make a B in the last exam.

6 0
3 years ago
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PIT_PIT [208]

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IceJOKER [234]

Answer:3

Step-by-step explanation:

Go up from one point to the other and whatever the number comes is the answer.

5 0
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