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podryga [215]
3 years ago
5

Find the missing dimension:if the perimeter is 6yards and the length is 6ft .what is the width?in yards

Mathematics
1 answer:
larisa [96]3 years ago
8 0
Since you haven't identified this figure, I'm going to assume that it's a rectangle.

The Perimeter of a rectangle of length L and width W is P = 2L + 2W.

Here you are given the Perimeter and the length, and are to find the width, W.

Solving the above equation for W, we get P - 2L = 2W.
Dividing by 2 (to isolate that W), we get 

P
-- - L = W
 2

Substitute P= 6 yds and L = 6 feet (or 2 yds), find W (in yards).
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4^2[1/3+4(36÷6)] Show work please.
Vaselesa [24]

Answer:

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Step-by-step explanation:

Simplify the following:

4^2 (4×36/6 + 1/3)

4×36/6 = (4×36)/6:

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Put 1/3 + 24 over the common denominator 3. 1/3 + 24 = 1/3 + (3×24)/3:

16 1/3 + (3×24)/3

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16 (1/3 + 72/3)

1/3 + 72/3 = (1 + 72)/3:

16 (1 + 72)/3

1 + 72 = 73:

16×73/3

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(16×73)/3

| | 7 | 3

× | | 1 | 6

| 4 | 3 | 8

| 7 | 3 | 0

1 | 1 | 6 | 8:

Answer:  1168/3

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3 years ago
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