The period of the function can be calculated using <span><span><span>2π</span><span>|b|</span></span><span><span>2π</span><span>|b|</span></span></span>.Period: <span><span><span>2π</span><span>|b|</span></span><span><span>2π</span><span>|b|</span></span></span>Replace <span>bb</span> with <span>11</span> in the formula for period.Period: <span><span><span>2π</span><span>|1|</span></span></span>
Answer:
5 or 45
Step-by-step explanation:
If the first term is "a" and the common ratio is "r", then the first three terms are ...
a, ar, ar²
Their product will be ...
a × ar × ar² = (ar)³ = 3375
ar = ∛3375 = 15
Their sum will be ...
a + ar + ar² = 65 = 15/r + 15 + 15r
Subtracting 15 and multiplying by r/5, we have the quadratic in r:
10r = 3 + 3r²
3r² -10r +3 = 0 . . . . in standard form
(3r -1)(r -3) = 0 . . . . factored
r = 1/3 . . or . . 3 . . . . values of r that make the factors zero
The first term is 15/r = 45 or 5
_____
The first three terms could be 5, 15, 45; or they could be 45, 15, 5.
The given statement is An integer is divisible by 100 if and only if its last two digits are zeros.
The two conditional statements that can be made are:
1) If an integer is divisible by 100 its last two digits are zeros.
This is a true statement. If a number is divisible by 100, it means 100 must be a factor of that number. When 100 will be multiplied by the remaining factors, the number will have the last two digits zeros.
<h3>What happen when last two digit of the number are 0?</h3>
2) If the last two digits of an integer are zeros, it is divisible by 100.
This is also true. If the last two digits are zeros, this means 100 is a factor of the integer. So the number will be divisible by 100.
Therefore, the two conditional statements that are formed are both true.
So, option A is the correct answer.
Yes, it is. When the definition is separated into two conditional statements, both of the statements are true.
To learn more about the integer visit:
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Answer:
See the bolded parts below. It corresponds to the blanks we have to fill in for each step.
Step-by-step explanation:
Taking a look at the figure, we see that KL ║ MN, ( which is given, as you can see ) while MJ and NJ act each as a transversal. This is a key point that will help us.
2. For step 2, we see that ∠JKL ≅ ∠JMN, while ∠JLK ≅ ∠JNM. This is true is they are present as corresponding angles, on either transversal. We can fill in this blank with " Corresponding angles. "
3. Therefore, for this 3rd step triangles JKL and JMN will be similar by " angle angle similarity. " After all, ∠JKL ≅ ∠JMN / ∠JLK ≅ ∠JNM.
4. This step can be proved by the " Proportionality of Corresponding Parts in Similar Triangles. " As you can see, the triangles are similar - and hence their parts correspond to one another.
5. I believe you mean step 5 to be " JM = JK + KM and JN = JL + LN. " That being said this is true by the " Partition Postulate, " which states that a whole is composed of it's parts.
6. This step substituted the 5th step into the 4th step. Therefore, it can be stated as " Substitute step 5 ➡ step 4. "
7. And for this last step here you can say " Simplify further. "
Answer:
we are looking for F
but in the question it stated that f(n) and at the end it also stated that f(1) so n=1
Step-by-step explanation:
we are using BODMAS
f(n-1)+1
f(1-1)+1=0+1
f=1
