First, converting R percent to r a decimal
r = R/100 = 6%/100 = 0.06 per year,
putting time into years for simplicity,
4 months ÷ 12 months/year = 0.333333 years,
then, solving our equation
I = $ 376.00
I = 18800 × 0.06 × 0.333333 = 375.999624
I = $ 376.00
The simple interest accumulated
on a principal of $ 18,800.00
at a rate of 6% per year
for 0.333333 years (4 months) is $ 376.00.
Answer:
Yes it is, because...
Step-by-step explanation:
This is an inequality, so you can treat it as an algebraic expression.
The first step is to multiple both sides by 2, to get rid of the 2 on the left side.
Your equation will now look like this:
y >= 2y - 22
The next step is to get all the y variables to one side, now that its a lot more simplified. Subtract 2y from both sides to get:
-y >= -22
Finally, cancel out the negative on both sides of the equation to get the y as a positive y, all by itself. This will get you:
y <= 22
REMINDER: when you divide by a negative number, such as in this case dividing by -1 on both sides, the inequality sign will flip!
y = 18 works because it is less than 22. (:
Answer:
9
Step-by-step explanation:
3,000/ 270 = 11.11
100/ 11.11 = 9
cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
