Question

(05.01)A poster is shown below: A rectangle is shown. The length of the rectangle is labeled 12 feet. The width of the rectangle is labeled 3 feet. What are the dimensions if the poster is enlarged by a factor of five over two ? 7.5 ft by 30 ft 15 ft by 60 ft 1.5 ft by 6 ft 15 ft by 6 ft

Answer 1

Answer:

The correct answer is the first option: 7.5 ft by 30 ft.

Step-by-step explanation:

If a rectangle is enlarged by a certain factor, that means that its height and width are both enlarged by such a factor. The new dimensions of the rectangle are obtained by multiplying the old dimensions by the enlarging factor, therefor we can compute the new dimensions as:

$W_N = W_O \cdot f$

$H_N = H_O \cdot f$

Where $W_N$ is the new width, $W_O$ is the old width, $H_N$ is the new height, $H_O$ is the old height, and $f$ is the enlarging factor.

From the above we can finally get that:

$W_N = 3 \cdot \frac{5}{2} = \frac{15}{2} = 7.5 ft$

$H_N = 12 \cdot \frac{5}{2} = \frac{60}{2} = 30 ft$

Answer 2

Answer:

Option A) 7.5 ft by 30 ft

Step-by-step explanation:

We are given the following information:

Dimension of rectangle:

Length = 12 feet

Width = 3 feet

The poster is enlarged by a factor of $\frac{5}{2}$

After enlargement, we can write

$\text{Enlarged length} = \text{Original length}\times \text{Factor}\\\text{Length of Poster} = \text{Length of Rectangle}\times \displaystyle\frac{5}{2}\\\\\text{Length of Poster} = \frac{12\times 5}{2} = \frac{60}{2} = 30\text{ feet}\\\\\text{Width of Poster} = \text{Width of Rectangle}\times \displaystyle\frac{5}{2}\\\\\text{Width of Poster} = \frac{3\times 5}{2} = \frac{15}{2} = 7.5\text{ feet}$

The dimension of poster is 7.5 feet by 30 feet

Option A) 7.5 ft by 30 ft