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3 years ago

What time is 5 3/4 hours after 11:32 pm?

Mathematics

2 answers:

PilotLPTM [1.2K]3 years ago

8 0

5 3/4 hours after 11:32 pm should be 45mins

elixir [45]3 years ago

6 0

11:32 pm + 5 hours= 4:32pm

4:32 pm + 45 minutes = 5:17 pm

3/4 hour = 45 min

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{(5,2),(-6,2),(8,4),(5,13)}

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Answer:

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2 years ago

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Answer:

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2 years ago

Determine whether the three segment lengths will produce a triangle. Type yes or no in the space provided.

tresset_1 [31]

Answer:

20 , 20 , 30 will produce a triangle

Step-by-step explanation:

* Lets study how to know if the lengths of the three segments

can formed a triangle

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- Lets study some examples

# If the lengths of the three segments are 5 , 6 , 7

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# If the lengths of the three segments are 5 , 7 , 12

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* Now lets solve the problem

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3 years ago

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

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Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

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3 years ago

Rotundo to the nearest 10 of 569

Brums [2.3K]

569 rounded to the nearest 10 would be 570.
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3 years ago

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