All categories

3 years ago

What is 89,659 rounded to the nearest hundred thousand?

Mathematics

2 answers:

n200080 [17]3 years ago

4 0

Answer:

100,000

Explanation:

To round a number to the nearest hundred thousands, we need to check the digit in the ten thousands position:

1- If this digit is less than 5, we will round down. This means that the digit in the hundred thousands position will remain the same and all digits after it will be converted to zeroes

2- If this digit is equal to or greater than 5, we will round up. This means that we will add one to the digit in the hundred thousands position and convert all digit after it to zeroes

Now, the given number is:

89,659

The digit in the hundred thousands position is 0

The digit in the ten thousands position is 8 which is greater than 5. Therefore, we will round up following rule 2 written above

This means that 89,659 rounded to the nearest hundred thousands would be 100,000

Hope this helps :)

Tom [10]3 years ago

3 0

Well because the hundred thousandth place is 100,000 200,000 300,000 etc. then the nearest to 89,659 would be 100,000

You might be interested in

Write an equation in standard form that is perpendicular to x-4y=-6 and goes through (3, -6)

elena-s [515]

Answer:

3-6

Step-by-step explanation:

because the distributive property

6 0

4 years ago

2. Given that the radius of the Earth is 6340 Km. calculate the Surface Acer of earth

serious [3.7K]

Answer:

Step-by-step explanation:

The surface area of a sphere (which the earth is considered to be) = 4 pi r^2

pi = 3.14

r = 6340

Area = 4 * 3.14 * 6340 * 6340 = 504856736 square km.

You should either round this to 505,000,000 or express a value in scientific notation.

5.05 * 10^8

6 0

3 years ago

I DONT KNOW THESE! HELP!

kkurt [141]

Answer:

20. x = 5, y = -2

21. x = 11, y = 12

22. x = 22, y = 11

23. x = 11, y = 10

Step-by-step explanation:

20. Opposite sides in the parallelogram are congruent, so

$2y+18=3x-1\\ \\6x-3=17-5y$

Solve this system of two equations:

$\left\{\begin{array}{l}2y-3x=-19\\ \\6x+5y=20\end{array}\right.$

Multiply the first equation by 2 and add two equations:

$2(2y-3x)+6x+5y=2\cdot (-19)+20\\ \\4y-6x+6x+5y=-38+20\\ \\9y=-18\\ \\y=-2$

Substitute it into the first equation:

$2\cdot (-2)-3x=-19\\ \\-3x=-19+4\\ \\-3x=-15\\ \\x=5$

21. Opposite angles in the parallelogram are congruent, so

$11x+5=10y+6$

Consecutive angles are supplementary, so

$6x-y+11x+5=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}11x-10y=1\\ \\17x-y=175\end{array}\right.$

From the second equation

$y=17x-175$

Substitute it into the first equation:

$11x-10(17x-175)=1\\ \\11x-170x+1750=1\\ \\-159x=-1749\\ \\x=11\\ \\y=17\cdot 11-175=187-175=12$

22. Opposite angles in the parallelogram are congruent, so

$2x-5=3y-12$

Consecutive angles are supplementary, so

$2x-5+7y+x=180^{\circ}$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-3y=-7\\ \\3x+7y=185\end{array}\right.$

From the first equation

$x=-3.5+1.5y$

Substitute it into the second equation:

$3(-3.5+1.5y)+7y=185\\ \\-10.5+4.5y+7y=185\\ \\-105+45y+70y=1,850\\ \\115y=1,850+105\\ \\115y=1,955\\ \\y=17\\ \\x=-3.5+1.5\cdot 17=22$

23. Opposite sides in the parallelogram are congruent, so

$2x+9=4y-9\\ \\3x-5=2y+8$

Solve this system of two equations:

$\left\{\begin{array}{l}2x-4y=-18\\ \\3x-2y=13\end{array}\right.$

Multiply the second equation by 2 and subtract it from the first equation:

$2x-4y-2(3x-2y)=-18-2\cdot 13\\ \\2x-4y-6x+4y=-18-26\\ \\-4x=-44\\ \\x=11$

Substitute it into the first equation:

$2\cdot 11-4y=-18\\ \\-4y=-18-22\\ \\-4y=-40\\ \\y=10$

3 0

3 years ago

HELP ASAP, PLZZZZZ

Novosadov [1.4K]

Answer:

Answer C: -5,0

Step-by-step explanation:

I'm probs way late, but there's your answer. Good luck to future exeminese!

4 0

3 years ago

Can y’all please help me . ASAP!!!

Veseljchak [2.6K]

Answer:

secx=\frac{1}{cosx}

Step-by-step explanation:

secx=\frac{1}{cosx}

5 0

3 years ago

Read 2 more answers