Answer:
5/9
Step-by-step explanation:
f(x) = 5 * 3^x
Let x = -2
f(-2) = 5 * 3^-2
We know a^-b = 1/a^b
= 5 * 1/3^2
= 5/9
The first three terms of sequence are 9 , 6 , 3
<em><u>Solution:</u></em>
Given the recursive function f(n) = f(n - 1) - 3
Where f(1) = 9
To find: First three terms of sequence
Substitute n = 2 , n = 3 and n = 4 in given recursive function
When n = 2
f(n) = f(n - 1) - 3
f(2) = f(2 - 1) - 3
f(2) = f(1) - 3
f(2) = 9 - 3 = 6
f(2) = 6
Thus second term is 6
When n = 3
f(3) = f( 3 - 1) - 3
f(3) = f(2) - 3
f(3) = 6 - 3 = 3
f(3) = 3
Thus the third term is 3
When n = 4
f(4) = f( 4 - 1) - 3
f(4) = f(3) - 3
f(4) = 3 - 3
f(4) = 0
Thus the fourth term is 0
Thus first three terms of sequence are 9 , 6 , 3
Add them together
e.g - 5a +6+6a+7
= 11a+13
Answer:
315
Step-by-step explanation:
7/4 of 180°
= 1.75 * 180
= 315°
Answer:
D.32
Step-by-step explanation:
25-18=7
18-11=7
11-4=7
