The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
<h3>Equation of a line</h3>
A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;
y - y1 = -1/m(x-x1)
where
m is the slope
(x1, y1) is the intercept
Given the following
Point = (4, -1)
Line: 2x-y - 7 = 0
Determine the slope
-y = -2x + 7
y= 2x - 7
Slope = 2
Substitute
y+1 = -1/2(x -4)
Write in slope-intercept form
2(y + 1) = -(x - 4)
2y+2 = -x + 4
2y = -x + 2
y = -1/2 + 1
Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
Learn more on equation of a line here: brainly.com/question/13763238
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Answer:
2k
Step-by-step explanation:
Let k is the ratio between two variables or y = kx
when x double, means: y = k (2x) = 2kx quantity y will change with a ratio 2k
3x - x + 8 + 5x - 2 = 10
combine like terms on the left, then add or subtract as asked
(3x - x + 5x) + (8 - 2) = 10
7x + 6 = 10
subtract 6 from both sides
7x = 4
divide both sides by 7
x = 4/7
Hope this helps! :)
Answer:
The answer is B
Step-by-step explanation:
just took the answer on e2020
Answer:6
Step-by-step explanation:
By going on a calculator and typing 81 then click divide then press 13.5
