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mixer [17]
2 years ago
5

Hey fellas, giving brainliest and a lot of points to who gets this correct​

Mathematics
1 answer:
Ainat [17]2 years ago
3 0

Answer:

7\frac{1}{12} or \frac{85}{12}

Step-by-step explanation:

total boxes = Jills boxes + Mikes boxes

total boxes = 5\frac{1}{3} +1\frac{3}{4}

                   = \frac{16}{3} + \frac{7}{4}

                   = \frac{64+21}{12}

                   = \frac{85}{12}

                   = 7\frac{1}{12}

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IRISSAK [1]

Answer:

You did not even start the meeting them you want us to join . Silly

Step-by-step explanation:

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how you doing?

how your day going?

8 0
3 years ago
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Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil
andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that p = 0.26

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that n = 5

4 failures, so 1 success, and we have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898

0.3898 = 38.98% probability that there will be 4 failures

4 0
3 years ago
Question 7:
padilas [110]

The answer is:

Nth term=200n-238

6 0
3 years ago
Write the resultant of the two vectors as an ordered pair. –6 5 and 6 –5
RideAnS [48]

Answer:

Resultant vector of two vectors is (0, 0).

Step-by-step explanation:

in this question two vectors having ordered pair (-6, 5) and (6, -5) have been given.

We can represent these vectors in the form of

\vec{A}=-6\hat{x}+5\hat{y}

and \vec{A'}=6\hat{x}+(-5)\hat{y}

Now the resultant of these vectors will be = A + A'

A + A' = \vec{A}=-6\hat{x}+5\hat{y} + \vec{A'}=6\hat{x}+(-5)\hat{y}

So the resultant vector = (0 + 0)

Therefore the resultant will be (0, 0)

8 0
3 years ago
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