Hey fellas, giving brainliest and a lot of points to who gets this correct
1 answer:
You might be interested in
Answer:
0.3898 = 38.98% probability that there will be 4 failures
Step-by-step explanation:
A sequence of Bernoulli trials forms the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Let the probability of success on a Bernoulli trial be 0.26.
This means that
a. In five Bernoulli trials, what is the probability that there will be 4 failures?
Five trials means that
4 failures, so 1 success, and we have to find P(X = 1).
0.3898 = 38.98% probability that there will be 4 failures
Answer:
Resultant vector of two vectors is (0, 0).
Step-by-step explanation:
in this question two vectors having ordered pair (-6, 5) and (6, -5) have been given.
We can represent these vectors in the form of
and
Now the resultant of these vectors will be = A + A'
A + A' = +
So the resultant vector = (0 + 0)
Therefore the resultant will be (0, 0)