Answer:
the answer is b
Step-by-step explanation:
i took the test it is b. The sum of the areas of faces A, B, and C.
OK first convert one of the equations into Y=MX+b form
Y-2x = 3
Add 2X
Y = 2x +3
Now substitute this equation in the other one.
So it would be
3X - 2Y = 5
3X-2(2x+3) = 5
Now solve for y
3X - 4X - 6 = 5
-1X - 6 = 5
Add 6
-1X = 11
X = -11
Now substitute this into one of the equations
Y - 2X = 3
Y -2(-11) = 3
Y +22 = 3
y = 3-22
y = -19
This problem cannot be solved unless we are given figure NPQR is a rhombus.
In that case, then all sides are equal, meaning
5x+16=9x-32
Solve for x
9x-5x=16+32
4x=48
x=12
Each side (including PQ) then equals 5x+16=5*12+16=76
Step One
Find AM
Formula
AM = MN - AN
Givens
MN = 67.2
AN = 32
Solution
AM - 67,2 - 32
AM = 35.2
Step Two
Set up a solution
67.2/35.2 = 81.9/x Cross Muliply
67.2 * x = 81.9 * 35.2 Combine the right
67.2 * x = 2882.88 Divide by 67.2
x = 2882.88/67.2
x = 42.9 Answer
Answer:
Yes
Step-by-step explanation:
The lines of symmetry are the three altitudes.
