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4 years ago

How many yards in 27 feet

Mathematics

2 answers:

Fittoniya [83]4 years ago

5 0

There are nine yards in 27 feet. Just divide 27 by three because there are three feet in a yard.

xxTIMURxx [149]4 years ago

4 0

There are 3 feet in a yard so divide 27 by 3 to get 9 yards

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A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

4 years ago

I need to change the subject to x

ira [324]

Answer:

h) (x+4t²)/4= 3V

x+4t²= 4*3V

x+4t²=12V

x=12V-4t²

MN=√(3x-2)

(MN)²=3x-2

3x-2=(MN)²

3x=(MN)²+2

x= [(MN)²+2]/3

7 0

3 years ago

What are parallel lines and perpendicular lines

lana66690 [7]

Answer:

Parallel run next to each other perpendicular are like paralell lines. If that makes sence

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Solve the given equation. If necessary, round to four decimal places. log2 3 + log2 a = log2 10

cestrela7 [59]

Answer:

3.333 if the equation is: $\log_2(3)+\log_2(a)=\log_2(10)$

Step-by-step explanation:

Looks like you are saying those are base logarithms.

I think you have the equation:

$\log_2(3)+\log_2(a)=\log_2(10)$

Use product rule, that is, $\log(uv)=\log(u)+\log(v)$ .

$\log_2(3\cdot a)=\log_2(10)$

Both sides are the same except the insides. If we want the left hand side to be the same as the right hand side, then we need 3a and 10 to be the same.

When are those the same?

Set them equal and find out!

3a=10

Divide boht sides by 3:

a=10/3

Perform the division in your calculator:

10 division sign 3

gives you 3.333333333(repeating).

8 0

3 years ago

Find all relative extrema of the function. Use the Second Derivative Test where applicable. (If an answer does not exist, enter

Lapatulllka [165]

Answer:

Relative minimum: $\left(-\frac{5}{2}, -\frac{33}{4}\right)$ , Relative maximum: $DNE$

Step-by-step explanation:

First, we obtain the First and Second Derivatives of the polynomic function:

First Derivative

$f'(x) = 2\cdot x + 5$ (1)

Second Derivative

$f''(x) = 2$ (2)

Now, we proceed with the First Derivative Test on (1):

$2\cdot x + 5 = 0$

$x = -\frac{5}{2}$

The critical point is $-\frac{5}{2}$ .

As the second derivative is a constant function, we know that critical point leads to a minimum by Second Derivative Test, since $f\left(-\frac{5}{2}\right) > 0$ .

Lastly, we find the remaining component associated with the critical point by direct evaluation of the function:

$f\left(-\frac{5}{2} \right) = \left(-\frac{5}{2} \right)^{2} + 5\cdot \left(-\frac{5}{2} \right) - 2$

$f\left(-\frac{5}{2} \right) = -\frac{33}{4}$

There are relative maxima.

6 0

3 years ago