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4 years ago

When a second identical bulb is added in series to a circuit with a single bulb, the resistance of the circuit

Physics

1 answer:

Arturiano [62]4 years ago

8 0

Answer:

Will double

Explanation:

The total resistance of a circuit with n resistors in series is equal to the sum of the individual resistances:

$R_T = R_1 + R_2 + ... + R_n$

In this problem, we have a circuit with initially one light bulb of resistance R, so the total resistance of the circuit is:

$R_T = R$

Later, a second identical bulb (so, same resistance R) is added in series to the circuit; so applying the previous formula, we see that the new total resistance is

$R_T = R + R = 2 R$

So, the resistance has doubled.

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The percent by which the fundamental frequency changed if the tension is increased by 30 percent is ? a)-20.04% b)-40.12% c)-30%

nika2105 [10]

Answer:

Percentage increase in the fundamental frequency is

d)-14.02%

Explanation:

As we know that fundamental frequency of the wave in string is given as

$f_o = \frac{1}{2L}\sqrt{\frac{T}{\mu}}$

now it is given that tension is increased by 30%

so here we will have

$T' = T(1 + 0.30)$

$T' = 1.30T$

now new value of fundamental frequency is given as

$f_o' = \frac{1}{2L}\sqrt{\frac{1.30T}{\mu}}$

now we have

$f_o' = \sqrt{1.3}f_o$

so here percentage change in the fundamental frequency is given as

$change = \frac{f_o' - f_o}{f_o} \times 100$

% change = 14.02%

3 0

3 years ago

A driver traveling at 40 m/s slams on his brakes the vehicle completely stops in five seconds how far to the vehicle go while st

lara [203]

Answer: 100 m

Explanation:

Initial speed(u) = 40 m/s

Final speed(v) = 0 m/s

Acceleration = v-u/t

=> 0-40/5

=> 8 m/s^2

Displacement= s

=> 2as = v^2-u^2

=> 2(-8)(s) = 0 - (40)^2

=> -16s = -1600

s = 100 m

We can say the vehicle move 100 meters before stopping.

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Artemon [7]

A factor of 50dB = a factor of 10^(50/10) = 10^5 = a factor of <em>100,000</em> .

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