Answer:
1.98 atm
Explanation:
Given that:
Temperature = 28.0 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (28 + 273.15) K = 301.15 K
n = 1
V = 0.500 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L atm/ K mol
Applying the equation as:
P × 0.500 L = 1 ×0.0821 L atm/ K mol × 301.15 K
⇒P (ideal) = 49.45 atm
Using Van der Waal's equation
R = 0.0821 L atm/ K mol
Where, a and b are constants.
For Ar, given that:
So, a = 1.345 atm L² / mol²
b = 0.03219 L / mol
So,


⇒P (real) = 47.47 atm
Difference in pressure = 49.45 atm - 47.47 atm = 1.98 atm
London is making in their room by the way I’m just using this as
Free pouts
<span>3040. Pascals.
The density of olive oil is 0.911 g/cm^3 and the density of water is 1.000 g/cm^3.
To calculate the pressure of 1 cm of water,
1000 kg/m^3 * 9.8 m/s^2 * 0.01 m = 98.000 Pa
To calculate the pressure of 1 cm of olive oil
911 kg/m^3 * 9.8 m/s^2 * 0.01 m = 89.278 Pa
Now to calculate the pressure at the bottom of the container, simply add the products of how many cm of each fluid you have. So
21 * 98.000 Pa + 11 * 89.278 Pa = 2058 Pa + 982.058 Pa = 3040.058 Pa
So the pressure at the bottom of the container will be 3040. Pascals.</span>