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PolarNik [594]
3 years ago
8

A driver traveling at 40 m/s slams on his brakes the vehicle completely stops in five seconds how far to the vehicle go while st

opping
Physics
2 answers:
Goshia [24]3 years ago
4 0

Answer:

200m

Explanation:

Velocity = displacement/time

V = s/t

Given

Velocity = 40m/s

Time = 5 secs

Therefore

40 = S/5

Cross multiply

S = 40 x 5

S = 200m

The vehicle travelled 200m before stopping

lara [203]3 years ago
3 0

Answer: 100 m

Explanation:

Initial speed(u) = 40 m/s

Final speed(v) = 0 m/s

Acceleration = v-u/t

=> 0-40/5

=> 8 m/s^2

Displacement= s

=> 2as = v^2-u^2

=> 2(-8)(s) = 0 - (40)^2

=> -16s = -1600

s = 100 m

We can say the vehicle move 100 meters before stopping.

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What are the physical and chemical properties of sodium?
Hitman42 [59]

Answer:

Physical Properties of Sodium

Atomic number 11

Melting point 97.82°C (208.1°F)

Boiling point 881.4°C (1618°F)

Volume increase on melting 2.70%

Latent heat of fusion 27.0 cal/g

Lenntech Water treatment & purification

Toggle navigation

Home Periodic table Elements Sodium

Sodium - Na

Chemical properties of sodium - Health effects of sodium - Environmental effects of sodium

Atomic number

11

Atomic mass

22.98977 g.mol -1

Electronegativity according to Pauling

0.9

Density

0.97 g.cm -3 at 20 °C

Melting point

97.5 °C

Boiling point

883 °C

Vanderwaals radius

0.196 nm

Ionic radius

0.095 (+1) nm

Isotopes

3

Electronic shell

[Ne] 3s1

Energy of first ionisation

495.7 kJ.mol -1

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2 years ago
Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at a speed 2v, wh
mel-nik [20]

Answer:u=\frac{v}{2}\sqrt{5-4sin\phi }

Explanation:

Given

Both cars mass is m

and solving problem in Vertical and horizontal direction

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4u^2=4v^2+v^2-4v^2sin\phi

4u^2=5v^2-4v^2sin\phi

u=\frac{v}{2}\sqrt{5-4sin\phi }

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hope this helps

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