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Dennis_Churaev [7]
3 years ago
15

What is 1/2 + 2/3? Im stupid so I don't know what this is. idk I'm dumb

Mathematics
2 answers:
nadezda [96]3 years ago
6 0

Answer:

1/2 + 2/3 = 1 1/6

Step-by-step explanation:+

1/2 + 2/3 = ?

Find the common denominator.

3/6 + 4/6 = 7/6

Turn your improper fraction into a mixed number.

1 1/6

Dmitry [639]3 years ago
3 0

<u>Answer:</u>

=7/6 pls mark me as brainlist

<u>Step-by-step explanation:</u>

1/2+2/3

=find lcm = 6

=1x3/2x3 +2x2/3x2

3/6+4/6

=7/6

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Jim buys a calculator that is marked 30% off. If he paid $35, what was the original price?
liraira [26]

Answer:

x = 50

Step-by-step explanation:

Let x be the original price.

He got 30% off

The discount is .30x

Subtract this from the original price to get the price he paid

x - .30x = price he paid

.70x = price he paid

.70x = 35

Divide each side  by .7

.70x/.7 = 35/.7

x=50

5 0
3 years ago
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Mia has two more than three times the number of model cars that Orville has. If Orville has c model cars, Which algebraic expres
Ahat [919]

Answer:

3c+2 is the correct answer

3 0
3 years ago
You sell instruments at a Caribbean music festival. You earn $326 by selling 12 sets of maracas, 6 sets of claves, and xx djembe
ELEN [110]

Answer: An equation we can use to find the number of djembe drums you sold be

12m+6c+dxx=$326

Step-by-step explanation:

Let price of maracas be m

Let the price of claves be c

Let the price of djembe drums be d

Number of maracas = 12 sets

Number of clavas = 6 sets

Number of djembe drums be xx

Total earned amount = $326

According to question,

12m+6c+dxx=$326

Hence, an equation we can use to find the number of djembe drums you sold be

12m+6c+dxx=$326

5 0
3 years ago
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Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the fiv
Dahasolnce [82]

Answer and Explanation:

Given : Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the​ X-linked genetic disorder.

To find :

a. Does the table show a probability distribution?

b. Find the mean and standard deviation of the random variable x.

Solution :

a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.029+0.147+0.324+0.324+0.147+0.029

\sum P(X)=1

Yes it is a probability distribution.

b) First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.029         0              0                0

1     0.147        0.147           1              0.147

2    0.324       0.648         4              1.296

3    0.324       0.972         9              2.916

4    0.147        0.588        16              2.352

5    0.029       0.145         25            0.725

   ∑P(x)=1      ∑xP(x)=2.5               ∑x²P(x)=7.436

The mean of the random variable is

\mu=\sum xP(x)=2.5

The standard deviation of the random sample is

Variance=\sigma^2

\sigma^2=\sum x^2P(x)-\mu^2

\sigma^2=7.436-(2.5)^2

\sigma^2=7.436-6.25

\sigma^2=1.186

\sigma=\sqrt{1.186}

\sigma=1.08

Therefore, The mean is 2.5 and the standard deviation is 1.08.

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3 years ago
. Resolver la siguiente inecuación, utilizar la notación de intervalos y representar el conjunto
Nimfa-mama [501]

Answer:

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3 0
3 years ago
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