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harina [27]
2 years ago
12

25÷5 + 12+5×2 solve this bodmas sum

Mathematics
2 answers:
Tomtit [17]2 years ago
4 0

Answer:

5+12+5×2

5+12+10

27

According to BODMAS Rule the ans is 27

expeople1 [14]2 years ago
3 0

Answer:

27

Step-by-step explanation:

25÷5+ 12+5×2

=5+12+5x2

=5+12+10

=17+10

=27

Hope this helps! Thanks.

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Solve for x : 13x + 7 = -227
Grace [21]

Answer:

-18

Step-by-step explanation:

1. Subtract 7 from both sides:

13x = -234

2. Divide 13 from both sides:

13x/13 = -234/13

x = -18

hope this helps!

7 0
2 years ago
I need help on the Quadratic Formula.
sasho [114]
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    x = <u>-12 +/- √(144 + 180)</u>
                           6
    x = <u>-12 +/- √(324)
</u>                     6<u>
</u>    x = <u>-12 +/- 18 </u>
                  6
    x = -2 <u>+</u> 3
    x = -2 + 3                 x = -2 - 3
    x = 1                         x = -5
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2. 5x² + 11x + 2 = 0
    x = <u>-(11) +/- √((11)² - 4(5)(2))</u>
                           2(5)
    x = <u>-11 +/- √(121 - 40)</u>
                       10
    x = <u>-11 +/- √(81)
</u>                  10
    x = <u>-11 +/- 9</u>
                10
    x = -1¹/₁₀ <u>+</u> ⁹/₁₀
    x = -1¹/₁₀ + ⁹/₁₀        x = -1¹/₁₀ - ⁹/₁₀
    x = ¹/₅                      x = -2
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3. 2x² - 11x + 14 = 0
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    x = <u>11 +/- √(121 - 102)</u>
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    x = <u>11 +/- √(9)</u>
                  6
    x = <u>11 +/- 3</u>
                6
    x = 1⁵/₆ <u>+</u> ¹/₂
    x = 1⁵/₆ + ¹/₂          x = 1⁵/₆ - ¹/₂
    x = 2¹/₃                  x = 1¹/₃
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4. 2x² - x - 15 = 0
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<u />
4 0
3 years ago
George makes two transactions today what can be the sum of 78+ (-34) mean in terms of George bank account
Alinara [238K]
Aacanding th the title a tite sic is 7R t Cz4
78t1-341=78-34=44 iThe iome is psitive aad the withdraual is
regative
so the sum TRIc-3) is mean the situation of the Gearge's acount
after the two transactions today


Gerge is bank account cared 44 today
8 0
2 years ago
Simplify this expression 2x^4 x x^3​
Fed [463]

Answer:

2x^7

Step-by-step explanation:

Multiply  

x ^4  by  x ^3  by adding the exponents.

4 0
3 years ago
Read 2 more answers
Give an example of each of the following, or argue that such a request is impossible.
Masteriza [31]

Answer and Step-by-step explanation:

Solution:

(a) Let (bn) be a bounded sequence of (an) then, Bolzano- Weierstrass theorem,

(bn) contains a subsequence that is converges.

(b) The sequence :

Xn = 1 + (-1) n / 2 + 1/n

Clearly, (xn) does not contain 1 or 0.

If we take sequence (x2n), then it converges to 1 and when we take sequence (x2n+1),

Then it converges to 0.

(c) The sequence:

1

1,1/2

1, 1/2, 1/3

1, 1/2, 1/3, 1/4

i.e

(xn) = (1,1/2, 1, 1/2, 1/3, …)

Then, the subsequence (xn) that is identically ½ in second column and 1/3 is third column and so on.

It has sub sequence that converges to every point in infinite set {1, 1/2, 1/3, 1/4, 1/5…}.

(d) The sequence

{1, 1/2, 1/3, 1/4, 1/5…}

if we take sequence of given set, then, this set converges to zero. This is not contained in it.

If (xn) converges to every point in set {1, 1/2, 1/3 …} then there exists subsequence which converges to 0. And 0 does not belong to given set.

3 0
3 years ago
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