78.5= (3.14)r^2
25=r^2
5=r
So, the radius of a circle with an area is 78.5 cm^2 is 5 cm^2
Answer:
Step-by-step explanation:
If two numbers have the same base, add the powers
5³ * 5⁴ = 5⁽³⁺⁴⁾ = 5⁷
Answer:
<u>Given rhombus ABCD with</u>
- m∠EAD = 67°, CE = 5, DE = 12
<u>Properties of a rhombus:</u>
- All sides are congruent
- Diagonals are perpendicular
- Diagonals are angle bisectors
- Diagonals bisect each other
<u>Solution, considering the above properties</u>
- 1. m∠AED = 90°, as angle between diagonals
- 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
- 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
- 4. AE = CE = 5, as E is midpoint of AC
- 5. BE = DE = 12, as E is midpoint of BD
Y=25x is proportional. Unit rate is 25
The other 2 aren't because they have a y-intercept and don't cross the orgin
Answer:
6/4
Step-by-step explanation:
All second numbers are divisible by 3 except for this ratio
