All categories

3 years ago

NEED HELP ASAP

Mathematics

2 answers:

Archy [21]3 years ago

7 0

I think its c your welcome

natita [175]3 years ago

4 0

Hello! I just took the quiz but my answers were A and B because of the way that they were ordered, but in this problem yours is A and D! (:

You might be interested in

Find the slope of a line that goes through point A(8,-4) and C(2, -1)

Black_prince [1.1K]

The answer for finding the slope is -1/2

5 0

2 years ago

3 out of five picks are orange . If 12 picks are orange , how many picks are there in all?

tekilochka [14]

20 picks in total .

8 0

3 years ago

How many grams are 2.7x10-^4 grams

andrew-mc [135]

Answer:

0,00027 grams!

Step-by-step explanation:

This is a scientific notation problem.

When a number is followed by a $10^{-1}$ , it means that said number has one zero at the beginning.

In this case, the number is followed by $10^{-4}$ , so that means that 2.7 has four zeros at the beginning. So, 2.7x $10^{-4}$ grams is equal to 0,00027 grams! (always the comma goes after the first zero).

6 0

3 years ago

Which three side lengths could make a triangle?

Tpy6a [65]

Answer:

9cm 5cm 12cm

Step-by-step explanation:

6 0

2 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

2 years ago