Answer:
25000 fragments
Explanation:
A restriction enzyme can cut a random DNA sequence once per every 4^n where n = number of bases in the recognition site of enzyme.
There are 6 bases in Xbal's recognition site (TCTAGA) so it will cut once per every 4^6 = 4096 bases (4kb).
Total genomic size = 100000kb
So expected number of fragments = Total genomic size/Size of one fragment
= 100000/4
= 25000 fragments
Answer:It will by the growth of them
Explanation:
Answer:
Gene
Explanation:
A segment of a DNA molecule (a sequence of bases) that codes for a particular protein and determines the traits (phenotype) of the individual. A gene is the basic unit of heredity in a living organism
