Ask question

Ask question

All categories

3 years ago

12

A 20.0 kg sled is being pulled across a horizontal surface at constant velocity. The pulling force has a magnitude of 80.0N and

is directed at an angle of 30.0º above the horizontal. Determine the coefficient of kinetic friction.

1 answer:

SSSSS [86.1K]3 years ago

7 0

U = F/R = 80/200cos30
u = 80/100√3
u= 0.46

You might be interested in

What does 5/7c=13/14 equal

natita [175]

To find c, you must isolate it.
To do this, you must divide both sides by 5/7, since that is being multiplied by c and you must do the inverse to it to cancel it out in order to leave c by itself.

5/7c ÷ 5/7 = c

13/14 ÷ 5/7
To divide fractions, follow these steps:
Step 1- Turn the second fraction, 5/7 in this case, into its reciprocal. This means swapping the places of the numerator and denominator.
5/7 reciprocal = 7/5

Step 2- multiply the original first fraction and reciprocal second fraction.
13/14 • 7/5
13 • 7 = 91
14 • 5 = 70
13/14 ÷ 5/7 = 91/70

Step 3- Simplify if possible.
91/70
Since 70 can go into 90, you can turn this into a mixed number.
1 and 21/70
Now simplify 21/70.
Both can be divided by 7.
21 ÷ 7 = 3
70 ÷ 7 = 10
So simplified, 91/70 equals 1 and 3/10.
As a decimal, this is 1.3.

So the answer is c = 1.3, or 1 and 3/10.

Hope this helps :)

8 0

3 years ago

Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th

alexandr1967 [171]

I'm guessing the function is

$f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}$

which, split into partial fractions, is equivalent to

$\dfrac1{x-6}-\dfrac1{x+2}$

Recall that for $|x|$ we have

$\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n$

With some rearranging, we find

$\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n$

valid for $\left|\dfrac x6\right|$ , or $|x|$ , and

$\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

valid for $\left|-\dfrac x2\right|$ , or $|x|$ .

So we have

$f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n$

$f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)$

$f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n$

Taken together, the power series for $f(x)$ can only converge for $|x|$ , or $-2$ .

6 0

2 years ago

The ratio of 10 to pencil is 2/7 if you count 84 pencil how many pain would you expect to find

frosja888 [35]

How much pain would you find? hopefully none, since you'd have lots of pens and pencils :).

$\bf \cfrac{pens}{pencils}\qquad \cfrac{2}{7}\qquad 2:7\qquad \qquad \cfrac{\stackrel{pens}{p}}{\stackrel{pencils}{84}}=\cfrac{2}{7}\implies p=\cfrac{84\cdot 2}{7}$

6 0

3 years ago

A basketball league plays a total of 90 games. How many teams are in the league if each team plays every other team twice?

REY [17]

Since the League itself is 90 games, and we know that each team will play each other twice, The equation can be written as:

90÷2

♡There are 45 teams in the basketball league.♡

5 0

3 years ago

A group incoming first-year students at Major University were surveyed in order to determine the factors that influenced their d

Ray Of Light [21]

Answer:

Step-by-step explanation:

This is a problem of SETS.

Start by listing out important data:

1. Total that said F = 55

2. Total that said P = 51

3. Total that said O = 61

4. F only = 9

5. F ∩ P ∩ O = 26 [NOTE: If you were to draw a Venn Diagram, 26 would be in the innermost circle because it comprises all three categories]

6. F ∩ P = 31

7. P only = 8

8. Students that said none of the 3 reasons = 4

QUESTIONS

1. How many said O and P? In other words, find the intersect of O and P. Find O ∩ P

2. How many said either F or O? [Answer to be gotten using a venn diagram] Find F ∪ P which translates to "F union P"

3. How many said F without saying P? [Answer to be gotten from the venn diagram as well]

4. How many students in total were surveyed? [HINT: Remember to include the 4 students that had none of the three options]

5 0

3 years ago