Answer:
none of the choices is correct
Step-by-step explanation:
To find the length of the side of square 1, divide the perimeter, 104÷4 = 27
That is the hypotenuse of the triangle.
The square of 27 is 729
Subtract the given square of Square 2, 576
729 - 576 = 153
Take the square root of 153 to find the length of the side of Square 3
√153= 12.37
I hope this helps. It's just a bit more challenging version of Pythagorean Theorem: a² + b² = c²
Answer:
b. cosine t less than 0 and cotangent t greater than 0
Step-by-step explanation:
We have the following relation
![\frac{\pi }{2} < t](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%3C%20t%20%3C%5Cpi)
if we apply the cosine function in the relation we get:
![cos\frac{\pi }{2}](https://tex.z-dn.net/?f=cos%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%3Ccost%3Ccos%5Cpi)
![-1](https://tex.z-dn.net/?f=-1%3Ccost%3C0)
the cosine of t is between 0 and -1 then (cosine t less than 0)
If we now apply cotangent function in the relation:
![cotan\frac{\pi }{2}](https://tex.z-dn.net/?f=cotan%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%3Ccotan%28t%29%3Ccotan%5Cpi)
![0](https://tex.z-dn.net/?f=0%20%3Ccotan%28t%29%3C%5Cinfty)
This means that cotang is greater than 0, therefore the correct answer is b. cosine t less than 0 and cotangent t greater than 0
(-4) means that it would be +4