The rephrased statement for Kun's proof is: A. In quadrilateral ABCD, if AB ≅ DC & AD ≅ BC, then AB║DC & AD║BC.
<h3>What is a Parallelogram?</h3>
A parallelogram is a quadrilateral that has two opposite sides that are congruent to each other and are also parallel to each other.
This means that if two pairs of opposite sides of a quadrilateral are congruent and parallel, then it is a parallelogram.
Rephrasing Kun's statement in his proof will therefore be: A. In quadrilateral ABCD, if AB ≅ DC & AD ≅ BC, then AB║DC & AD║BC.
Learn more about a parallelogram on:
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I'm pretty sure that the answer to the fudge cakes is 8 friends
Area of Parallelogram ABCD is equivalent to the area of rectangle AXBY.
Area of rectangle AXBY= Length AX * Length AB= 3 ft * 4√2 ft = 12√2 sq.ft.
Thus Area of Parallelogram is 12√2 sq.ft.
I would say that the answer is probably 40
