Question

PLEASE HELP

Answer 1

Part A
The given line passes through (-2,2) and it is parallel to the line

$4x - 3y - 7 = 0$


We need to determine the slope of this line by writing it in slope -intercept form.


$3y = 4x - 7$


$y = \frac{4}{3} x - \frac{7}{3}$
The slope of this line is
$\frac{4}{3}$


The line parallel to this line also has slope

$m = \frac{4}{3}$


The equation is

$y = \frac{4}{3} x + c$


We substitute (-2,2)

$2 = \frac{4}{3}( - 2) + c$


$c = 2 + \frac{8}{3} = \frac{14}{3}$


The required equation is


$y = \frac{4}{3} x + \frac{14}{3}$


PART B


The given line is


$4x - 3y - 7 = 0$




The slope of this line is
$\frac{4}{3}$


The slope of the line perpendicular to it is

$m = - \frac{3}{4}$

The equation of the line is

$y = - \frac{ 3}{4} x + c$




We substitute the point, (-2,2)



$2= - \frac{ 3}{4} ( - 2) + c$


$2= \frac{ 3}{2} + c$



$c = 2 - \frac{3}{2} = \frac{1}{2}$


The equation of the perpendicular line is


$y= - \frac{ 3}{4} x + \frac{1}{2}$