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3 years ago

Giveaway 100 POINTS!!

Mathematics

2 answers:

Basile [38]3 years ago

6 0

Answer:

count me in

Step-by-step explanation:

Murrr4er [49]3 years ago

6 0

Thank you so much :)

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Which statement is true

Alinara [238K]

The answer is C. half of 10 x 7

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3 years ago

Given the sequence 8, 16, 32, 64, ..., which expression would give the thirteenth term?

mrs_skeptik [129]

8, 16, 32, 64,…
×2 ×2 ×2

$a_{n} = a_{1} * r^{n - 1}$
$a_{n} = 8 * 2^{13 - 1}$
$a_{n} = 8 * 2^{12}$
$a_{n} = 8 * 4096$
$a_{n} = 32768$

   First Term: 8
      Second Term: 16
      Third Term: 32
      Fourth Term: 64
       Fifth Term: 128
      Sixth Term: 256
   Seventh Term: 512
   Eighth Term: 1024
   Ninth Term: 2048
      Tenth Term: 4096
   Eleventh Term: 8192
   Twelfth Term: 16384
Thirteenth Term: 32768

$The\ expression\ that\ would\ give\ the\ thirteenth\ term\ of\ the\ problem\ would\ be\ the\ equation\ of\ the\ geometric\ sequence,\ which\ is\ equal\ to\ a_{n} = a_{1} * r^{n - 1}.$

5 0

3 years ago

Read 2 more answers

You have purchased a new warehouse. To finance the purchase, you’ve arranged for a 25-year mortgage for 75 percent of the $4,200

Cerrena [4.2K]

\begin{aligned}Payment=183000\\ \cos t=4200000\cdot 0,75\% =3150000=c\\ Payment=C\dfrac {\left( 1+i\right) ^{n}\cdot i}{\left( 1+i\right) ^{n}-1}\\ n=25years\times \dfrac {12manths}{1year}=300months\\ 18300=3150000\cdot \dfrac {\left( 1+i\right) ^{300}\cdot i}{\left( 1+i\right) ^{300}\cdot i}\\ i=0,0041\\ i is the monhly interest_{i}\\ i\times 12months=APR\\ APR=0,0123=1,23%\end{aligned}

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3 years ago

Evaluate a(4b + c2) if a = 2, b = 5, and c = 1.

Maksim231197 [3]

Answer:

Step-by-step explanation:

a = 2, b = 5, and c = 1

a*(4b + c²) = ⇒ plug in values
2*(4*5 + 1²) = ⇒ solving exponents
2*(20 + 1) = ⇒ parenthesis
2*21 = ⇒ multiplication
42 ⇒ answer

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3 years ago

Read 2 more answers

Find the zeroes of the following equation:

weqwewe [10]

Answer: $\bold{x=\dfrac{1\pm \sqrt5}{2}}$

both zeros are irrational numbers

<u>Step-by-step explanation:</u>

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

$\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}$

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3 years ago