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Amiraneli [1.4K]
2 years ago
9

Help me please I wold appreciated it

Mathematics
1 answer:
algol132 years ago
5 0

Answer:

BD=7

ED=5

BE=7

AD=10

AE=5

Step-by-step explanation:

given CD = 7 you use that to find BD and BE because CD´s line length is the same as BD and BE

given BC = 5 you use that to find ED and AE and AD because BC is the same length as ED (they create the same triangle) and than given AE also equals 5 you add ED and AE to get AD

hope this helps

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There are 6 numbers. That means you have to divide 465 by 6 to get the mean.

Divide:

465 / 6 = 77.5

The answer is D. 77.5

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What is the solution of the equation? w - 2 = -3
Viktor [21]
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3 years ago
A package weighs 80 ounces. What is the weight of the package in pounds?
Degger [83]

Answer:

5

Step-by-step explanation:

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3 0
2 years ago
Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x
Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

y=a(x-h)^2+k  

(where (h, k) is the vertex)

Given:

  • vertex = (1, -108)

\implies y=a(x-1)^2-108

Given:

  • y-intercept = (0, -105)

\implies a(0-1)^2-108=-105

\implies a(-1)^2=-105+108

\implies a=3

Therefore:

\implies y=3(x-1)^2-108

The x-intercepts are when y = 0

\implies 3(x-1)^2-108=0

\implies 3(x-1)^2=108

\implies (x-1)^2=36

\implies x-1=\pm \sqrt{36}

\implies x=1\pm 6

\implies x=7, x=-5

Therefore, the x-intercepts are (7, 0) and (-5, 0)

7 0
2 years ago
How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
konstantin123 [22]

440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

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Thus 440 gallons of 80 % antifreeze solution must be mixed

4 0
2 years ago
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