No, 1/a^b (a^-b) doesn't equal -a^b
<h3>
Therefore they are perpendicular.</h3>
Step-by-step explanation:
A equation of line is
y =mx +c
Here the slope of the line is m.
Given equations are
x - 2y = 18
⇔-2y = -x +18
............(1)
and 2x + y = 6
⇔y = -2x +6 ............(2)
Therefore the slope of equation (1) is
= 
Therefore the slope of equation (2) is
= -2
If two lines are perpendicular, when we multiply their slope we get -1.
therefore,
=
. (-2) = -1
Therefore they are perpendicular.
Undefined slope is rise/0
run is equal to 0
that means it doesn't go left or right
means it is vertcal
means it is x=somethig
(x,y)
(-6,4)
x=-6 is the equation
oh, forgot about standard form
standard form is
ax+by=c
so
x+0y=-6 would be the equation in standard form
Answer: 95%
Step-by-step explanation: