Answer:
The probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.
Step-by-step explanation:
Since a politician is about to give a campaign speech and is holding a stack of thirteen cue cards, of which the first 3 are the most important, and just before the speech, she drops all of the cards and picks them up in a random order, to determine what is the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack, the following calculation must be performed:
1/13 x 1/13 x 1/13 = X
0.076 x 0.076 x 0.076 = X
0.00045 = X
0.00045 x 100 = 0.045
Therefore, the probability that cards # 1, # 2, and # 3 are still in order on the top of the stack is 0.045%.
Decimal to percent...multiply by 100...2.39 x 100 = 239%
just so u know...
percent to decimal...divide by 100
2x - y = 6
5x + 10y = -10
<span>( 2x - y = 6 ) * 5
</span>10x - 5y = 30
<span>( 5x + 10y = -10 ) * 2
</span>10x + 20y = -20
If we subtract the last 2 equations,
30y = -50
y = -(5/3)
2x - (-5/3) = 6
2x + (5/3) = 6
2x = 6 - (5/3)
2x = (18-5)/3
2x = 13/3
x = 13/6
Give me the whole question including information, and graphs.
Is is it a function Bcoz 4 and 0 has only one out. When you have one in and two out that's means is not a function.