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Colt1911 [192]
3 years ago
15

E^2x -2e^x -8=0

xFormula1" title=" {e}^{2x} - {2e}^{x} - 8 = 0" alt=" {e}^{2x} - {2e}^{x} - 8 = 0" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0
E^2x -2e^x -8=0   =>    e<span>^(2x)  -2e^x -8=0

Temporarily replace e^x with y.

Then (y)^2 - 2y - 8 = 0.  Factors are (y-4) and (y+2).

Roots are y = 4 and y= -2.

Now remembering that we temporarily replaced e^x with y, we let 
y=4 = e^x.  We need to solve for x.  Taking the natural log of both sides, we get:

ln 4 = x (answer)

We have to discard the other root (y= -2), because we cannot take the ln of a negative number.


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A population of deer mice consists of 200 individuals and has an r = 0.1. A population of wood rats consists of 100 individuals
Mariulka [41]

Answer:

Population of dice mice after one year = 2000

Population of wood rats after one year = 1000

The population of deer mice is growing faster than the popular of wood rats

Step-by-step explanation:

The expression for population = dN/dt = rN

Upon integration N = rN²/2

Therefore for population N = 200 and r= 0.1

N after one year = (0.1 x 200²)/ 2 = 2000

Therefore for population N = 100 and r= 0.2

N after one year = (0.2 x 100²)/ 2 = 1000

Hence the population of deer mice is growing faster than the popular of wood rats

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2 years ago
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3 years ago
Someone please help!
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Please help me with this. an explanation would be great as well
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Answer:

A

Step-by-step explanation:

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