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Snezhnost [94]
3 years ago
6

If 3× :8=24:16find the value of x given that ×>0

Mathematics
2 answers:
ASHA 777 [7]3 years ago
4 0

Answer: 4

<u>Step-by-step explanation:</u>

  3(x)  :   8

<u>  *2    </u>: <u>  *2  </u>

=   24  :  16


⇒ 6x = 24

⇒   x  = 4

Alex3 years ago
4 0

Answer:

x = 4

Step-by-step explanation:

Expressing the ratios in equivalent fraction form, that is

\frac{3x}{8} = \frac{24}{16} ( cross- multiply )

48x = 192 ( divide both sides by 48 )

x = 4


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Dennis_Churaev [7]

Answer:

Brand C

Step-by-step explanation:

7 0
2 years ago
I need help please help me quick
sergejj [24]

Count the squares in between each letter.

Point Q is 6 units from Point R

Point R is 7 units from Point T

Point T is 3 units from Point S

For the area, it is easiest to take the area of each of those shapes and then add them.

(3*7/2) + (6*7)

10.5 + 42 = 52.5 Square Units

3 0
3 years ago
Work out this question pls
KatRina [158]

Answer:

3 3/16

Step-by-step explanation:

Conversion a mixed number 8 1/2

to a improper fraction: 8 1/2=8×2+1/2=16+1/2=17/2

To find a new numerator:

a) Multiply the whole number 2 by the denominator 3. Whole number 2 equally 2×3/3= 6/

3

b) Add the answer from previous step 6 to the numerator 2. New numerator is 6 + 2 = 8

c) Write a previous answer (new numerator 8) over the denominator 3.

Two and two thirds is eight thirds

Divide: 17/2×8/3=17/2×3/8=17×3/2×8= 51/

16

Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of 8/3 is 3/8) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. In the following intermediate step, it cannot further simplify the fraction result by canceling.

In other words - seventeen halves divided by eight thirds = fifty-one sixteenths.

51/16

3 3/16

7 0
2 years ago
The length of a rectangle is three times it’s width. The area of the rectangle is 48 square centimeters. Find the measures of th
denis-greek [22]
---------------------------------------------------------------------------------
Define length and width
---------------------------------------------------------------------------------
Let the width be x
Width = x
Length = 3x

---------------------------------------------------------------------------------
Form equation and solve for x
---------------------------------------------------------------------------------
x(3x) = 48
3x² = 48
x² = 48 ÷ 3
x² = 16
x = √16
x = 4

---------------------------------------------------------------------------------
Find length and width
---------------------------------------------------------------------------------
Width = x = 4
Length = 3x = 3(4) = 12

---------------------------------------------------------------------------------
Answer: Width = 4cm, Length = 12cm
---------------------------------------------------------------------------------
7 0
3 years ago
write the given equation into vertex form and sketch the graph. Determine the domain and range f(x)=3x^2-6+2 plss help
LuckyWell [14K]

Answer: the range would thus be [-3, 1/3].)

Step-by-step explanation:

1. To sketch the function f(x) = (2/3)x - 3, we first need to find two points that we can later join to sketch the line, for example the x- and y-intercepts.

a) The x-intercept occurs when f(x) = 0, so if f(x) = 0, then:

f(x) = (2/3)x - 3

0 = (2/3)x - 3

3 = (2/3)x (Add three to both sides)

3*(3/2) = x (Multiply both sides by 3/2)

9/2 = x

We have now found the x-intercept at (9/2, 0)

b) The y-intercept occurs when x = 0, so:

f(x) = (2/3)x - 3

f(0) = (2/3)*0 - 3

f(0) = -3

Now we know that the y-intercept is at (0, -3)

c) All that's left is to sketch the graph axes and label them, plot the two points, join them together using a ruler and label their coordinates.

2. The Domain is the range of x-values for which the function exists, and the Range is the range of y-values for which the function exists.

Since there haven't been any constraints specified, we can say that both the Domain and Range are (-∞, ∞), since the graph continues forever both along the x- and y-axis.

(Note that this isn't always the case and would change if, for example, the question stipulated that there was a domain of [0, 5] and you had to find the range. Then, you would calculate the value of y at each end of the domain (if x = 0, y = -3 and if x = 5, y = 1/3) - in my example, the range would thus be [-3, 1/3].)

4 0
3 years ago
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