We're going to remedy it with the parallelogram law.
= one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN
sin
/3 = sin(eighty)/three.304 = 63.4 stages
3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4
Answer:
Explanation:
a)
Given that:
V = 25 mi/hr
To ft/sec, we have:
A = 25ft²
Recall that:
The drag force
For 70 miles per hour, we have:
The drag force
Answer: yes,
Explanation: the higher lifted then the more potential energy consumed by the object
Answer:
2. A force of 50 N is applied to the object for a distance of 2.0 m. Assume that object(the mass of the object is 3kg)
was at rest at the beginning, what speed did it achieved because of the work done on it? (Hint:
Calculate the works performed by the force first.)
I figured that is 8.2m/S,I am just not sure can anyone help me i much appreciate it.