Answer:
The value is
Explanation:
From the question we are told that
The focal length of the objective is
The focal length of the eyepiece is
The tube length is
Generally the magnitude of the overall magnification is mathematically represented as
Where is the objective magnification which is mathematically represented as
=>
=>
is the eyepiece magnification which is mathematically evaluated as
So
Answer:
4.15 m/s
Explanation:
As the total energy must be conserved (neglecting air resistance) the change in gravitational potential energy, must be equal to the change in kinetic energy:
ΔE = ΔK + ΔU =0
If we take as a zero reference level for the gravitational potential energy, the height of the swing seat above the ground, (which is equal to 0.21 m), we can find the initial gravitational energy, considering the height of the point where the seat is released, regarding this point:
h₀ = 1.09 m -0.21 m = 0.88 m
⇒ U₀ = m*g*h₀ = 400 N*0.88 m = 352 J
As Uf = 0, ΔU = Uf -U₀ = -352 J
As the swing starts from rest, K₀=0, so we can say:
ΔK = Kf = (1)
As ΔK = -ΔU ⇒ ΔK = 352 J (2)
From (1) and (2) we can solve for vf, as follows:
So, when the swing passes through its lowest position, Betty moves at 4.15 m/s.
The acceleration due to gravity would be 5.95 m/s²
A force is known to be a push or pull and it is the change in momentum per time. It can be expressed by using the relation.
From the parameters given:
By replacing the given values into the above equation, we can determine the acceleration.
∴
625 N = 105 kg × acceleration.
acceleration = 5.95 N/kg
acceleration = 5.95 m/s²
Learn more about acceleration(a) here: