Not sure the precise concept of "normal observation", but I assume that is observed by "eyes".
Eye observation is basically macroscopic, but when you use a mark, which can be regarded as a point of mass, then it goes to microscopic.
Mark is a reference point which you can compare the relative position change, but with your eyes, first you cannot notice microscopic changes, second the eyes cannot precisely set a stable reference point.
Answer:
a) h = 8.02 10³ m b) yes
Explanation:
a) The pressure in a fluid is given by
P = ρ g h
The pressure in this case is the atmospheric pressure, 1.013 105 Pa, let's clear the height (h)
h = P / ρ g
h = 1.013 10⁵ / (1.29 9.8)
h = 8.02 10³ m
b) The height of Mount Everest is 8848 m
It is above this height, according to this model there would be no air to breathe
Answer:
a)ΔV = 6.48 KV
b)ΔU =18.79 mJ
Explanation:
Given that
E= 1.8 KV/m
a)
We know that
Electric potential difference ΔV given as
ΔV = E .d
Here
E= 1.8 KV/m
d= 3.6 m
ΔV = E .d
ΔV = 1.8 x 3.6 KV
ΔV = 6.48 KV
b)
Given that
q=+2.90 µC
Change in electric potential energy ΔU given as
ΔU = q .ΔV
ΔU =18.79 mJ
