This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
C and D
150(1+2.5) and 150(3.5)
Step-by-step explanation:
Given that,
Directrix, d= -5, and eccentricity, e = 2.
The polar equation of the conic is given by :
Put all the values,
As e>1, it is a hyperbola. Hence, this is the required solution.
Answer: 2.26
Step-by-step explanation://Give thanks(and or Brainliest) if helpful (≧▽≦)//
