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3 years ago

How to solve approximate square roots

Mathematics

1 answer:

Murljashka [212]3 years ago

5 0

Just follow this operation.
Find the two perfectly squared factors the multiple to your number.
Take the square root of those perfect factors then multiple them.

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Help! can someone please give me the answer

AlladinOne [14]

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Pliss

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3 years ago

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The given equation has been solved in the table. Step Statement 1.) 3x - 10 = -16 2.) 3x - 10 + 10 = -16 +10 3.) 3x = - 6 4.) 3x

FinnZ [79.3K]

The answer is

In step 2, the addition property of equality was applied.

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Proof that the answer is correct.

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4 years ago

PLEASE. HELP. SERIOUSLY PLEASE.

Crazy boy [7]

Answer:

x value would be 2

Step-by-step explanation:

The computation is shown below:

Given that

x^2 + 2x = 8

x^2 + 2x - 8 = 0

x^2 + 4x - 2x - 8 = 0

x(x + 4) - 2(x + 4) = 0

(x - 2) (x + 4) = 0

So, x value would be 2

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3 years ago

Which of the following explains why f(x) = log4x does not have a y-intercept?

Margarita [4]

Answer: f(x) approaches infinity

Step-by-step explanation:

N/A

7 0

3 years ago

According to industry sources, online banking is expected to take off in the near future. The projected number of households (in

Airida [17]

Answer:

(a) The least-square regression line is: $y=4.662+2.709x$ .

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

$y=\alpha +\beta x$

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

(a)

The formula to compute intercept and slope is:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \end{aligned}$

The values of ∑X, ∑Y, ∑XY and ∑X² are computed in the table below.

Compute the value of intercept and slope as follows:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}$

The least-square regression line is:

$y=4.662+2.709x$

(b)

For the year 2007 the value of x is 10.

Compute the value of y for x = 10 as follows:

$y=4.662+2.709x$

$=4.662+(2.709\times10)\\=4.662+27.09\\=31.752\\\approx 31.8$

Thus, the number of households using online banking at the beginning of 2007 is 31.8.

5 0

3 years ago