Let his normal weight = 100%
He is 10% more so he is 110%
Divide his weight now by 110% to find his normal weight.
88/1.1 = 80
His normal weight is 80 kg
Answer:15
Explanation: I just did it and that's what i ready said lol
Answer:
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Step-by-step explanation:
Answer:
E = 1.81 × 10⁻¹⁸ J
ν = 2.73 × 10¹⁵ Hz
Step-by-step explanation:
We can calculate the frequency (ν) of an ultraviolet photon with wavelength (λ) 110 nm, using the following expression.
c = λ . ν
where,
c is the speed of light
ν = c / λ
ν = (3.00 × 10⁸ m/s) / 110 × 10⁻⁹ m
ν = 2.73 × 10¹⁵ s⁻¹ = 2.73 × 10¹⁵ Hz
We can calculate the energy (E) of the photon using the Planck-Einstein equation.
E = h × ν
where,
h is the Planck's constant
E = h × ν
E = 6.63 × 10⁻³⁴ J.s × 2.73 × 10¹⁵ s⁻¹
E = 1.81 × 10⁻¹⁸ J
The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).
<h3>What is a circle?</h3>
It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
Prove algebraically that the straight line with equation x = 2y + 5 is a tangent to the circle with equation x² + y² = 5.
x = 2y + 5 ...1
x² + y² = 5 ...2
If the intersection of the point of the circle and line is one. Then the line is tangent to the circle.
Then from equations 1 and 2, we have
(2y + 5)² + y² = 5
4y² + 25 + 20y + y² - 5 = 0
5y² + 20y + 20 = 0
5y² + 10y + 10y + 20 = 0
5y (y + 2) + 10(y + 2) = 0
(5y + 10)(y + 2) = 0
y = -2, -2
Then the value of y is unique then the value of x will be unique.
The value of x will be
x = 2(-2) + 5
x = -4 + 5
x = 1
The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).
More about the circle link is given below.
brainly.com/question/11833983
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