How are you supposed to solve this???
Answer:
12.4 in
Step-by-step explanation:
I whish i can help :)
The vertex is at the point (0,0) and the focus at the point (0, 1/8). This is given to us. Both the vertex and focus are separated by a vertical distance in the positive direction.
This means that the parabola opens upward. The vertex form of the equation for a parabola that opens upward is:
y = a(x - h)^2 + k, where the point
(h, k) is the vertex of the parabola.
Plug the vertex given into the above equation.
y = a(x - 0)^2 + 0
y = ax^2 + 0
y = ax^2
What is a?
Note: a = 1/(4f), where f is the distance from the vertex to the focus or simply as given in the focus point above 1/8.
Let f = 1/8
a = 1/4(1/8)
a = 1/(1/2)
a = 2
The equation we want is
y = 2x^2.
f(x) = 2x^2
Choice A is the answer.
Answer:
y=1/3x-6
Step-by-step explanation:
Answer:
Follows are the solution to the given points:
Step-by-step explanation:
In point A:
In point B:
In point C:
For df = 70, the top 5% critical t score
tcrit = 1.666914479
Thus,
In point D:
For df = 70, the top 5% critical t score
tcrit = -1.666914479
In point E:
The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is
tcrit = -1.293762898
In point F:
The lower cutoff is 0.90 in the center, which would be around 80 %. The critical point therefore is
tcrit = 1.293762898
