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bonufazy [111]
3 years ago
13

Pls help, it due ASAP.....pls show workings

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0

Answer:

12 going across from point A to B and A to c is 14 so... 12+14=26

hope this helps!!! :)

Step-by-step explanation:

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Find the interquartile range of the data.
likoan [24]

The answer is 14. Here is how I work it out.


First we are going have to identify quartile 1 and quartile 3.


So after putting the numbers in order from least to greatest mark the number with a half way point.

This is optional but it will help us spot the sections better.


31,33,35,41,43,|46,48,49,49,50

Next put parentheses around the remaining groups of numbers.

(31,33,35,41,43,)|(46,48,49,49,50)


For the next step we have to find the median of each group.


(31,33,35,41,43,)|(46,48,49,49,50)


The median of each group, are called the quartiles, the median of the lower half is quartile 1, and the median of the upper half is quartile 3.


Now subtract quartile 1 from quartile 3.


49 – 35 = 14


So the interquartile range of this data set is 14.

4 0
3 years ago
Simplify completely quantity 2 x squared plus 13 x plus 20 all over x squared minus 5 x minus 36 .
adoni [48]

Answer:

  • (2x + 5)/(x - 9)
  • 3. quantity 2 x plus 5 over x minus 9

Step-by-step explanation:

Quantity 2 x squared plus 13 x plus 20 all over x squared minus 5 x minus 36

  • (2x² + 13x + 20)/(x² -5x - 36) =
  • (2x²+ 5x + 8x + 20)/(x² - 9x + 4x -36)=
  • (2x + 5)(x + 4)/(x - 9)(x + 4) =
  • (2x + 5)/(x - 9)

Correct option is option 3

3 0
3 years ago
Solve for x.<br><br> x = <br><br> thank you in advance!
bija089 [108]

Answer:

3x+9=180(angles on a line

3x=180-9

3x=171

x=171/3

x=57

6 0
2 years ago
Read 2 more answers
I’m not sure on what to do for these problems…can someone help me please
Ray Of Light [21]

Answer:

You need to find k, the constant of proportionality, by dividing y with its corresponding x.

3 0
3 years ago
Factor completely x^8- 16.
Nataly_w [17]

Answer:

Step-by-step explanation:


So in this example we'll be using the difference of squares which essentially states that: (a-b)(a+b)=a^2-b^2 or another way to think of it would be: a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}). So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

x^8-16 = (x^4-4)(x^4+4)

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

x^4-4 = (x^2-2)(x^2+2)

So completely factored form is: (x^2-2)(x^2+4)(x^4+4)

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because x^2+4 = x^2-(-4). and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i) just something that might be useful in some cases.

7 0
2 years ago
Read 2 more answers
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