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hjlf
3 years ago
14

Order these numbers from least to greatest. 171/20 8 7/11 7.549 8.59

Mathematics
2 answers:
Ratling [72]3 years ago
8 0
<h2>Hopefully this helps :)</h2><h2 /><h2>7.549, 8.59, 8 7/11, 171/20</h2>
tiny-mole [99]3 years ago
3 0

Answer:

7.549, \frac{171}{20}, 8.59, 8\frac{7}{11}

Step-by-step explanation:

You notice the last 2 in the sequence are decimals. So you convert everything else to decimals too.

So begin with dividing 171/20 which gets you 8.55

Then convert the second fraction to a regular fraction, by multiplying the denominator by the bigger number beside it, 8.

So 8 * 11 = 88

Then add the numerator to the new product.

88 + 7 = 95

Then you have your new numerator.

Take that and divide by 11

95/11 = 8.63

So from least to greatest is

7.549, \frac{171}{20}, 8.59, 8\frac{7}{11}

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Answer:

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Step-by-step explanation:

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The first term in a geometric sequence is 54, and the 5th term is 2 / 3. Find an explicit form for the geometric sequence.
quester [9]

Answer:  ar^{n-1}=54(\dfrac{1}{3})^{n-1}

Step-by-step explanation:

The nth term for a geometric sequence is given by :-

a_n=ar^{n-1}    (1)

We are given that The first term in a geometric sequence is 54. i.e. a=54

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Put n=5 and a= 54 in (1), we get

a_5=(54)r^{4}=     (3)

From (2) and (3), we have

\Rightarrow(54)r^{4}=\dfrac{2}{3}\\\\\Rightarrow r^4=\dfrac{2}{3}\times\dfrac{1}{54}=\dfrac{1}{3\times27}=\dfrac{1}{81}\\\\\Rightarrow\ r=(\dfrac{1}{81})^{\frac{1}{4}}=\dfrac{1}{3}

Explicit form for the geometric sequence: ar^{n-1}=54(\dfrac{1}{3})^{n-1}

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3 years ago
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