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Nikolay [14]
4 years ago
9

If m<PQT=60 and m<PQS=4x+14 find the value if x

Mathematics
1 answer:
lutik1710 [3]4 years ago
8 0

Diagram is attached below

m<PQT=60 and m<PQS=4x+14

m<PQS  and m<SQT  are same

m<PQT = m<PQS + m<SQT = m<PQS + m<PQS = 2m<PQS

 m<PQT = 2m<PQS

So m<PQS = \frac{m

Plug in the given information and solve for x

4x + 14 = \frac{60}{2}

4x + 14 = 30 (subtract 14 on both sides)

4x = 16 (Divide by 4 on both sides)

x = 4

The value of x is 4

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Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?
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Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

sec^4 x + sec^2 x tan^2 x - 2 tan^4 x

Required

Simplify

(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2

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Represent tan^2x with b

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Recall that

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The expression (a -b) (a+ 2 b) becomes

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..............................................................................................................................

In trigonometry

sec^2x =1  +tan^2x

Subtract tan^2x from both sides

sec^2x - tan^2x =1  +tan^2x - tan^2x

sec^2x - tan^2x =1

..............................................................................................................................

Substitute 1 for sec^2x - tan^2x in (sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

(1) (sec^2x+ 2 tan^2x)

Open Bracket

sec^2x+ 2 tan^2x ------------------This is an equivalence

(secx)^2+ 2 (tanx)^2

Solving further;

................................................................................................................................

In trigonometry

secx = \frac{1}{cosx}

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Substitute the expressions for secx and tanx

................................................................................................................................

(secx)^2+ 2 (tanx)^2 becomes

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\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}

Add Fraction

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................................................................................................................................

In trigonometry

sin^2x + cos^2x= 1

Make sin^2x the subject of formula

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Substitute the expressions for 1  - cos^2x for sin^2x

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Open bracket

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