4 years ago

If m<PQT=60 and m<PQS=4x+14 find the value if x

Mathematics

1 answer:

lutik1710 [3]4 years ago

8 0

Diagram is attached below

m<PQT=60 and m<PQS=4x+14

m<PQS and m<SQT are same

m<PQT = m<PQS + m<SQT = m<PQS + m<PQS = 2m<PQS

m<PQT = 2m<PQS

So m<PQS = $\frac{m$

Plug in the given information and solve for x

4x + 14 = $\frac{60}{2}$

4x + 14 = 30 (subtract 14 on both sides)

4x = 16 (Divide by 4 on both sides)

x = 4

The value of x is 4

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(I NEED THIS ANSWERED QUICKLY! I WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!)

almond37 [142]

Answer:

Option A $\sqrt{187.95}\ Km$

Step-by-step explanation:

we know that

Applying the Pythagorean Theorem

$c^2=a^2+b^2$

where

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a and b are the legs

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$14.2^2=3.7^2+b^2$

solve for b

$b^2=14.2^2-3.7^2$

$b^2=187.95$

$b=\sqrt{187.95}\ Km$

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Nataliya [291]

Answer:

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